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Enthalpy of vaporisation of a liquid is 30KJmol^{-1} and entropy of vaporisation is 75Jmol^{-1}K^{-1}. The boiling point of the liquid at 1 atm (in K) is

Option: 1 250

Option: 2 400

Option: 3 450

Option: 4 600

Answers (1)

best_answer

As we learnt

 

Entropy for phase transition at constant volume -

 

\Delta S= \frac{\Delta E_{Transition}}{T}

- wherein

\Delta E\RightarrowInternal Energy

T\RightarrowTransitional temperature

 

 \Delta S= \frac{\Delta Q_{rev}}{T}\: \: \: \: or\: \: \: \: T=\frac{\Delta Q_{rev}}{\Delta S}

T=\frac{30*10^3}{75}= 400K

 

Posted by

rishi.raj

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