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Find horizontal distance (in meter) covered by the block when it hits ground . Assume all surfaces are frictionless and it is horizontal at Q.(Heght of point P from ground is 1m )

 

Option: 1 1

Option: 2 2

Option: 3 1.5

Option: 4 3

Answers (1)

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As we have learned

Conservative Force -

Work done by the force along a closed path is zero.

- wherein

Work done by the Conservative Force, i.e. Gravitational Force, depends only upon the initial and final position.

 

 Work done from P to Q 

W = mg (1- 0.5 ) = mg/2

\Delta W= (change \: \: in \: \: K.E)\\ so

\frac{mg}{2} = \frac{1}{2}mv^2 \Rightarrow v = \sqrt g

Time to reach ground

 t=\sqrt{\frac{2h}{g}} \\ t = \sqrt{\frac{2 \times 0.5 }{g }} = \frac{1}{\sqrt g }

Horizontal\ Distance = vt=\sqrt g \times \frac{1}{\sqrt g } = 1 m

 

 

 

 

Posted by

Suraj Bhandari

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