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  • FInd peak current (in amperes) in given circuit<div class='qna-op

FInd peak current (in amperes) in given circuit

Option: 1

0.628


Option: 2

1.34


Option: 3

0.444


Option: 4

0.222


Answers (1)

best_answer

As we learned

Peak Current -

{i}'_{0}= \frac{v_{0}}{X_{C}}= V_{0}\omega C= V_{0}\left ( 2\pi \nu C \right )

-

 

 V_{rms}=\frac{V_{o}}{\sqrt{2}}

V_{o}={\sqrt{2}}\times V_{rms}

V_{o}={\sqrt{2}}\times \frac{200}{\sqrt{2}}

Vo=200mV

Now, peak current, P_{o}=\frac{V_{o}}{X_{C}}

i_{o}=V_{o}WC=V_{o}\times 2\pi fc

i_{o}=200\times 2\times\pi \times50\times10\times10^{-3}

i_{o}=200\pi

i_{o}=0.628A

 

 

Posted by

Rakesh

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