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For the transistor circuit shown below, if \beta =100, voltage drop between emitter and base is \mathrm{0.7\ V} then value of \mathrm{VCE} will be

Option: 1

\mathrm{10\ V}


Option: 2

\mathrm{5\ V}


Option: 3

\mathrm{13\ V}


Option: 4

\mathrm{0\ V}


Answers (1)

best_answer

\begin{aligned} &\mathrm{ i_b=\frac{5-0.7}{8.6}=0.5 \mathrm{~mA} \Rightarrow I_c=\beta I_b=100 \times 0.5 \mathrm{~mA}} \\ &\mathrm{ \text { By using } V_{C E}=V_{C C}-I_c R_L=18-50 \times 10^{-3} \times 100=13 \mathrm{~V}} \end{aligned}

Posted by

Gautam harsolia

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