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If \mathrm{KMnO_4} is reduced by oxalic acid in an acidic medium, then oxidation number of Mn changes from

Option: 1

4 to 2


Option: 2

6 to 4


Option: 3

7 to 2


Option: 4

7 to 4


Answers (1)

best_answer

Oxalic acid reacts with acidified \mathrm{KMnO_4} and gets oxidised to \mathrm{CO_2} reducing the permanganate ions to \mathrm{Mn^{2+}}. The reaction is given as

\mathrm{2KMnO_4 + 3H_2SO_4 + 5(COOH)_2 \longrightarrow K_2SO_4 + 2MnSO_4 + 8H_2O + 10CO_2}

So, the oxidation state of Manganese changes from +7 to +2.

Therefore, option (3) is correct.

Posted by

Ritika Kankaria

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