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If one-liter glass flask contain some mercury. it is found that at different temp. the volume of air inside the flask remains the same. what is the volume If mercury (in cc)  in this flask 

if \ \ \left(\alpha_{g l a s s}=9 \times 10^{-6} /^{\circ} C, \gamma_{H g}=180 \times 10^{-6} /^{\circ} C\right)

Option: 1 50

Option: 2 100

Option: 3 150

Option: 4 200

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As we learned

 

Co-efficient of Real Expansion -

\gamma _{r}=\frac{Real\ increase\ in\ Volume}{Initial\ volume\times \Delta \theta}

\gamma _{r}=\frac{(\Delta v)_{r}}{v\times \Delta \theta}

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expansion in the volume of the vessel is exactly equal to the expansion in the volume of the mercury.

 \begin{array}{l}{(\Delta V)_{g}=V \gamma_{g} \Delta \theta=V .3 \alpha_{g} \Delta \theta} \\ {(\Delta V)_{m}=V_{m} \gamma_{m} \Delta \theta} \\ {(\Delta V)_{g}=(\Delta V)_{m} \Rightarrow 3 \alpha_{g} V=\gamma_{m} V_{m}} \\ {3 \times 9 \times 10^{-6} \times 1=180 \times 10^{6} V_{m}} \\ {V_{m}=0.15 \text { litre }=0.15 \times 1000=150 \mathrm{cm}^{3}=150 \ cc}\end{array}

 

 

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shivangi.shekhar

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