Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • If radius of second Bohr orbit of the ion is <img alt="105.8$ $\mathrm{pm}" src="/latex-image/?105.8%24%20%24%

If radius of second Bohr orbit of the \mathrm{He}^{+} ion is 105.8$ $\mathrm{pm}, what is the radius of third Bohr orbit of \mathrm{Li}^{2+}ion?
 

Option: 1

15.87 \mathrm{pm}
 


Option: 2

1.587 \mathrm{pm}
 


Option: 3

158.7 \mathrm{\AA }
 


Option: 4

158.7 \mathrm{pm}


Answers (1)

best_answer

We know,

\mathrm{r \propto \frac{n^{2}}{z} }\\

\mathrm{\therefore \frac{r\left(\mathrm{He}^{+}, n=2\right)}{r\left(\mathrm{Li}^{2+}, n=3\right)}=\frac{2^{2} \times 3}{2 \times 3^{2}}=\frac{2}{3} }

\mathrm{\therefore r\left(Li^{2+}, n=3\right) =\frac{3}{2} r\left(\mathrm{He}^{+}, n=2\right)} \\

                                =\frac{3}{2} \times 105.8 \\

                                =158.7 \mathrm{pm}

Hence correct option is 4

Posted by

Rakesh

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG result 2025 withheld? Reasons, implications; here’s what to do
anam-khan

NEET UG Result 2025: Allen Institute sweeps rankings with 4 in top 10, 39 in top 100
anam-khan

Mahesh Kumar from Rajasthan tops NEET UG 2025; secures AIR 1 rank, shares study plan, prep strategies

Latest Question