,
and
Let the number of secondary carbon atoms present in the above compounds are X, Y and Z respectively. Then, X + Y - Z is:
(Response should be in integer only lke 78).
5
4
6
7
,
and
Number of secondary carbon atoms
X = 6
Y = 4
Z = 5
X + Y - Z = 6 + 4 - 5 = 5
Ans = 5