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  • In a composite rod, when two rods of different length and of same cross-section area are joined end to end, then if K is the effective coefficient of thermal conductivity, then  <img alt=

In a composite rod, when two rods of different length and of same cross-section area are joined end to end, then if K is the effective coefficient of thermal conductivity, then  \frac{l_1 + l_2}{K} is equal to 

Option: 1

\frac{l_1}{K_1} - \frac{l_2}{K_2}


Option: 2

\frac{l_1}{K_2} - \frac{l_2}{K_1}


Option: 3

\frac{l_1}{K_1} + \frac{l_2}{K_2}


Option: 4

\frac{l_1}{K_1} + \frac{l_2}{K_2}


Answers (1)

best_answer

As we have learnt,

 

Equivalent Thermal Conductivity Series -

K_{s}=\frac{n}{\frac{1}{K_{1}}+\frac{1}{K_{2}}+--------\frac{1}{K_{n}}}

- wherein

For n slabs of equal length. 

 

 For series of combination R = R_1 + R_2

\\\Rightarrow \frac{l_1 + l_2}{KA} = \frac{l_1}{K_1A} + \frac{l_2}{K_2A} \\\Rightarrow \frac{l_1 + l_2}{K} = \frac{l_1}{K_1} + \frac{l_2}{K_2}

 

Posted by

Pankaj Sanodiya

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