In a series L-C-R circuit,
and
Ohm, when a constant D.C voltage E is applied to the circuit, the capacitor acquires a charge
The D.C. source is replaced by a sinusoidal voltage source in which the peak voltage
is equal to the constant D.C. voltage E. At resonance the peak value of the charge acquired by the capacitor will be :
C= 10-11F, L = 10-5Henry, and R= 100 ohm
= inductive reactance
= capacitive reactance
R is resistance
at resonance:
i.e Imax(R) = Vmax
Imax = Eo/R ......(1)
Calculation of Eo
initially, the circuit is connected with a constant battery source:
at steady state potential across the capacitor becomes = E = Eo
we know that
q = C E ( Given at steady state q= 10-9 C)
put values and get E as
E = Eo = 10-9/10-11 = 100 volt.............(2)
Put the value of Eo in equation (1)
Get Imax = 1 amp
The maximum value of potential difference across the capacitor is
Therefore, the peak value of the charge acquired by the capacitor is