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In an ideal transformer, the voltage and the current in the primary are 200 volt and 2 amp respectively. If the voltage in the secondary is 2000 volt. Then value of current in the secondary will be :       

Option: 1

 0.2 amp


Option: 2

2 amp              

 


Option: 3

10 amp


Option: 4

20 amp


Answers (1)

best_answer

 

Ideal transformer -

There is no loss of power.

- wherein

P_{out}= P_{in}

V_{s}\, {i}'_{s}= V_{in}i_{in}

 

 

Given :

    Voltage in primary V_{P} =200\; volt

    Current in primary i_{P}=2\; amp

   Voltage in secondaryV_{S}=2000 \; volt

    The relation for the current in the secondary is

\frac{v_{s}}{v_{p}}=\frac{i_{p}}{i_{s}}

 or  = 0.2 amp.

\frac{2000}{200}=\frac{2}{i_{s}}   or   i_s=\frac{2\times 200}{2000}=0.2A

Posted by

Gaurav

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