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  • In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is : (at. mass Ag=108; Br=80)<div class='qna-opti

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :
(at. mass Ag=108; Br=80)

Option: 1

24


Option: 2

36


Option: 3

48


Option: 4

60


Answers (1)

best_answer

We have given,

Weight of organic compound = 250mg

And, weight of AgBr = 141mg

Now, we know, % of Br is calculated in Carius method by the equation below:

\begin{array}{c}{\% \text { of } \mathrm{Br}=\frac{\text { Atomic weight of } \mathrm{Br}}{\text { Molecular weight of } \mathrm{Ag}\mathrm{Br}}} \times {\frac{\text { Weight of } \mathrm{AgBr}}{\text { Weight of organic bromide }} \times 100}\end{array}

Thus,

\% \text { of } \mathrm{Br}=\frac{80}{188} \times \frac{141}{250} \times 100=\frac{1128000}{47000}=24 \%

Therefore, Option(1) is correct

Posted by

Irshad Anwar

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