In the following reactions, products (A) and (B) respectively are: NaOH + Cl_{2}\rightarrow A +NaCl+ side\ product (hot and conc.) Ca(OH)_{2}+Cl_{2}\rightarrow B + CaCl_2+ side\ product (dry)
Option: 1 NaClO_{3}\ and\ Ca(ClO_{3})_{2}
Option: 2 NaOCl\ and\ Ca(OCl)_{2}
Option: 3 NaClO_{_{3}}\ and\ Ca(OCl)_{2}
Option: 4 NaOCl\ and\ Ca(ClO_{3})_{2}
 

Answers (1)

As we have learnt,

Chlorine reacts with NaOH and Ca(OH)_2 and undergoes disproportionation. The products depend upon the concentration of the base and also the temperature.

The reactions are given as 

2Na(OH) + 3 Cl_2 \longrightarrow NaClO_3 +5 NaCl + 3 H_2O

(Hot and Conc.)

2 Ca(OH)_2 + 2 Cl_2 \longrightarrow Ca(OCl)_2 + CaCl_2 + 2 H_2O

 (Dry)

Therefore, Option(4) is correct.

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