In this equation:
What will be the mass (in g) of O2 produced from 1.23g of KClO3?
0.482
0.545
0.758
0.345
According to the equation,
2 moles of KClO3 will produce 3 moles of O2.
Thus moles of KClO3 = 1.23 / 123
= 0.01 moles
Therefore, 0.01 moles of KClO3 will produce = (3 x 0.01) / 2
= 0.015 moles
thus mass of O2 = 0.015 x 32
= 0.48g
Therefore, Option(1) is correct