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  • Need clarity, kindly explain! The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

The correct  thermodynamic conditions for the spontaneous reaction at all temperatures is

  • Option 1)

    \Delta H< 0\ and\ \Delta S=0

  • Option 2)

    \Delta H> 0\ and\ \Delta S< 0

  • Option 3)

    \Delta H< 0\ and\ \Delta S> 0

  • Option 4)

    \Delta H< 0\ and\ \Delta S< 0

 

Answers (1)

best_answer

 

Spontanous process -

\Delta G= \Delta H-\Delta T

 

- wherein

For spontanouse process \Delta G must be negative.

 

 \Delta G=\Delta H-T \Delta S

For spontaneous \Delta G<0

Or, \Delta H-T \Delta S< 0

If \Delta H< 0\;\;and\;\;\Delta S=0

\Delta G=-ve\; \sigma -T(0)=-ve\; at all temperature.

Hence this also satisfies condition for spontaneous reaction.


Option 1)

\Delta H< 0\ and\ \Delta S=0

This option is incorrect.

Option 2)

\Delta H> 0\ and\ \Delta S< 0

This option is incorrect.

Option 3)

\Delta H< 0\ and\ \Delta S> 0

This option is correct.

Option 4)

\Delta H< 0\ and\ \Delta S< 0

This option is incorrect.

Posted by

Aadil

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