On heating 0.199 g of a metallic oxide in a current of hydrogen 0.045 g of water is formed. Find the equivalent weight of the metal.
31.8
35.7
24.9
28.4
Weight of metallic oxide = 0.199 g
Now, as 16g of oxygen is present in 18 g of H2O
Thus, O2 present in 0.045 g of H2O = (16 X 0.045) / 18
= 0.04 g
Weight of metal = 0.199 - 0.04
= 0.159
Thus, the equivalent weight of metal = (0.159 X 8) / 0.04
= 31.8