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  • On linear temperature scale Y, water freezes at 160o Y and boils at - 50o Y. On this Y scale, temperature of 340 K would be read as : ( water freezes at 273 K and bo

On linear temperature scale Y, water freezes at 160o Y and boils at - 50o Y. On this Y scale, temperature of 340 K would be read as : ( water freezes at 273 K and boils at 373 K ) 

Option: 1

-73.7^{o}Y


Option: 2

-233.7^{o}Y


Option: 3

-86.3^{o}Y


Option: 4

-106.3^{o}Y


Answers (1)

best_answer

 

Since the temperature scale is assumed to be linear, slope in two cases will be same. Hence,

\begin{aligned} &\frac{Y-(-160)}{-50-(-160)}=\frac{K-273}{373-273}\\ &\frac{Y+160}{110}=\frac{K-273}{100}\\ &Y=\frac{11}{10}(K-273)-160\\ &Y=\frac{11}{10}(340-273)-160=-86.3^{0} Y \end{aligned}

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rishi.raj

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