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  • One mol ideal gas is taken in a container of Volume 5L, it is then reversibly compressed to a volume of 3L. The temperature was kept constant during the process (310 K). Find out the work (

One mol ideal gas is taken in a container of Volume 5L, it is then reversibly compressed to a volume of 3L. The temperature was kept constant during the process (310 K). Find out the work (in KJ) done to compress the gas.

Option: 1

1.3


Option: 2

-1.5


Option: 3

-13


Option: 4

13


Answers (1)

best_answer

As we have learned,
The work done in the reversible isothermal process is \mathrm{W = -2.303nRT log(V_2/V_1)}
We have,

n = 1
\mathrm{T = 310K}
\mathrm{V_1 = 5L}
\mathrm{V_2 = 3L}
\mathrm{R = 8.314 J/mol.K}
Putting all the values we get,
\mathrm{W = -2.303 \times 1\times 8.314\times 310\times log(\frac{3}{5})= 1316 J}

\therefore \mathrm{W = 1.316\ kJ}

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Rishi

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