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Part of circular disc of mass M and radius R is removed and added to the same disc as shown in figure . The position of center of initial disc is 

Option: 1

-R/4 


Option: 2

R/2 


Option: 3

-R/2 


Option: 4

-R/8 


Answers (1)

best_answer

m1 &  \vec{r_{1}} are mass and position of the centre of mass for whole body. m2 & \vec{r_{2}} are mass and position of the centre of mass of added mass.

 

 superpose method 

     

 

x_{cm} = \frac{m_1 x_1 + m_2 x_2 -m_3x_3}{m_1+m_2-m_3}

x_{cm} = \frac{\sigma (\pi R^2)o+ \sigma \pi (\frac{R}{2})^2(\frac{-R}{2})-\sigma \pi \left ( \frac{R}{2} \right )^2(\frac{R}{2})}{\sigma (\pi R^2)+\frac{\sigma (\pi R^2}{4})-\frac{\sigma (\pi R^2)}{4}} \\\\ x_{cm} = \frac{- \pi \frac{R^2}{4}R}{\pi R^2} = \frac{-R}{4}

 

 

 

 

Posted by

manish painkra

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