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The apparent coefficient of expansion of liquid when heated in a copper vessel is c and when heated in a silver vessel is s .If A is the linear cofficient of expansion of copper then the linear cofficient of expansion of silver is :

 

Option: 1

\frac{c+s -3A}{3}


Option: 2

\frac{c+3A-s}{3}


Option: 3

\frac{s +3A-c}{3}


Option: 4

\frac{c+s +3A}{3}


Answers (1)

best_answer

As we learned

The apparent change in volume in liquid relative to vessel -

\Delta V_{apparent}=V\time\gamma_{app}\;\Delta \theta

=V(\gamma_{real}-\gamma_{vessel})\Delta \theta

=V(\gamma_{r}-3\alpha)\Delta \theta

- wherein

\gamma_{vessel}=3\alpha

\gamma _{r}= \gamma _{app}+\gamma _{vessel}

for copper;\gamma _{r}= c+3\: \alpha _{cu}=c+3A

for silver; \gamma _{r}=s+3\: \: \alpha _{Ag}

Since the coefficient of real expansion of liquid is the same in both the cases

\Rightarrow c+3A=s+3\: \: \alpha _{Ag}

\: \alpha _{Ag}= \frac{c+3A-s}{3}

Posted by

vinayak

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