Browse by Stream
-
Engineering and Architecture
Exams
Colleges
Predictors
Resources
-
Computer Application and IT
Quick Links
Colleges
-
Pharmacy
Colleges
Resources
-
Hospitality and Tourism
Colleges
Resources
Diploma Colleges
-
Competition
Other Exams
Resources
-
School
Exams
Top Schools
Products & Resources
-
Study Abroad
Top Countries
Resources
-
Arts, Commerce & Sciences
Colleges
Upcoming Events
Resources
-
Management and Business Administration
Colleges & Courses
Predictors
-
Learn
Law Preparation
MBA Preparation
Engineering Preparation
Medical Preparation
-
Online Courses and Certifications
Top Streams
Specializations
- Digital Marketing Certification Courses
- Cyber Security Certification Courses
- Artificial Intelligence Certification Courses
- Business Analytics Certification Courses
- Data Science Certification Courses
- Cloud Computing Certification Courses
- Machine Learning Certification Courses
- View All Certification Courses
Resources
-
Medicine and Allied Sciences
Colleges
Predictors
Resources
-
Law
Resources
Colleges
-
Animation and Design
Exams
Predictors & Articles
Colleges
Resources
-
Media, Mass Communication and Journalism
Colleges
Resources
-
Finance & Accounts
Top Courses & Careers
Colleges
Get Answers to all your Questions
The change in internal energy when a gas is cooled from 927bdegreeto 27 degree, is
A. 300% B. 200% C. 250% D. 75%
Answers (1)
@Aastha
T1 = 927 + 273 = 1200 K
T2 = 27 + 273 = 300 K
internal energy ∝ Temperature
U ∝ T
(U1 / U2) = (T1 / T2)
∴ [(U1 – U2) / U2] = [(T1 – T2) / T2]
∴ % change in energy = [{(1200 – 300) / (300)} × (100)]
= 3 × 100 = 300%
View full answer
NEET 2024 Most scoring concepts
- Just Study 32% of the NEET syllabus and Score up to 100% marks
