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The first and second ionisation enthalpies of a metal are \mathrm{496} and \mathrm{4560\; kJ\; mol^{-1}}, respectively. How many moles of \mathrm{HCl} and \mathrm{H_{2}SO_{4}}, respectively, will be needed to react completely with 1 mole of the metal hydroxide ?
 

Option: 1

\mathrm{1\ and\ 2}


Option: 2

\mathrm{1\ and\ 0.5}


Option: 3

\mathrm{1\ and\ 1}


Option: 4

\mathrm{2\ and\ 0.5}


Answers (1)

best_answer

According to the given data of I.E, this element must belong to group 1, and thus it is monovalent and forms hydroxide of the type M(OH).

\mathrm{MOH + HCl \longrightarrow MCl + H_2O}

\mathrm{2 MOH + H_2SO_4 \longrightarrow M_2SO_4 + 2H_2O}

Thus, from the reaction stoichiometry it is clear that 1 mole of the metal hydroxide requires 1 mole and 0.5 moles of HCl and H2SO4 respectively for complete neutralisation.

Hence, the option number (2) is correct.

Posted by

shivangi.bhatnagar

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