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  • The gas released during the detection of carbon in an organic compound is (X) and this gas turns lime water milky by forming the precipitate (Y). The gas (X) and the precipitate (Y) 

The gas released during the detection of carbon in an organic compound is (X) and this gas turns lime water milky by forming the precipitate (Y). The gas (X) and the precipitate (Y) respectively are :

Option: 1

\mathrm{CO _{2} \text { and } Ca ( OH )_{2}}


Option: 2

\mathrm{CO \text { and } CaCO _{3}}


Option: 3

\mathrm{CO _{2} \text { and } CaCO _{3}}


Option: 4

\mathrm{CO \text { and } Ca ( OH )_{2}}


Answers (1)

As we have learnt,

Carbon present in the compound is oxidised to \mathrm{CO_2} which is tested by Lime water.

When \mathrm{CO_2} is passed through lime water \mathrm{Ca(OH)_2} , it turns milky due to the formation of \mathrm{CaCO_3(s)} 

\mathrm{CO_2 + Ca(OH)_2 \longrightarrow CaCO_3 + 2\ H_2O}

Hence, the correct answer is Option (3)

Posted by

Kshitij

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