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  • The heat is flowing through two cylindrical rod of same material the diameters of the rods are in the ratio 1: 2 and their length are in the ratio 2 : 1 . If the temprature diffrence b/w their end

The heat is flowing through two cylindrical rod of same material the diameters of the rods are in the ratio 1: 2 and their length are in the ratio 2 : 1 . If the temprature diffrence b/w their end is same , the ratio of rate of flow of heat through them will be 

Option: 1

1:1 


Option: 2

2 :1 


Option: 3

1 :4 


Option: 4

1 : 8 


Answers (1)

best_answer

As we have learned

Heat Current -

I_{H}=\frac{\theta_{1}-\theta_{2}}{R_{th}}

- wherein

\theta_{1}-\theta_{2}= The temperature difference between the two ends of the conductor. 

 

 \frac{\Delta Q}{\Delta t} = \frac{\Delta \theta}{R} \Rightarrow \frac{(\frac{\Delta Q}{\Delta t})_1}{(\frac{\Delta Q}{\Delta t})_2}= \frac{R_2}{R_1}....(1)\\\\\\ R = \frac{l }{KA} \Rightarrow \frac{R_1}{R_2} = (\frac{l_1}{l_2})\cdot (\frac{A_2}{A_1})= \frac{2}{1} \cdot (\frac{2}{1})^2

\frac{R_1}{R_2}= 8/1....(2)\\\\

\frac{(\frac{\Delta Q}{\Delta t})_1}{(\frac{\Delta Q}{\Delta t})_2}= 1/8

Posted by

Rishabh

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