Get Answers to all your Questions

header-bg qa

The maximum work (in KJ) done in expanding 32\, g of Oxygen at 300K and occupying volume of 7 L isothermally until volume becomes 35 L is

Option: 1

4


Option: 2

-4


Option: 3

2


Option: 4

-2


Answers (1)

best_answer

As we have learned,
The work done in the reversible isothermal process is  \mathrm{W= -2.303nRT log(V_2/V_1)}

We have,

\mathrm{n = 32/32 = 1}
\mathrm{T = 300K}
\mathrm{V_1= 7L}
\mathrm{V_2= 35L}
\mathrm{R = 8.314 \, J / mol.K}

Putting all the values we get,
\mathrm{W = -2.303\times 1\times 8.314\times 300\times log\frac{35}{7}}
       = -4014J
       \mathrm{= -4.0\ KJ}
 

Posted by

Devendra Khairwa

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks