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  • The potential energy of a particle in a conservative field is given by   Force acting o

The potential energy of a particle in a conservative field is given by U = 20 \frac{xy }{z} 

Force acting on the particle is 

Option: 1

\left ( \frac{20y}{z} \right )\hat i+ \left ( \frac{20 x }{z } \right )\hat j + \left ( \frac{20 xy}{z^2 } \right ) \hat k


Option: 2

-\left ( \frac{20y}{z} \right )\hat i- \left ( \frac{20 x }{z } \right )\hat j + \left ( \frac{20 xy}{z^2 } \right ) \hat k


Option: 3

-\left ( \frac{20y}{z} \right )\hat i- \left ( \frac{20 x }{z } \right )\hat j - \left ( \frac{20 xy}{z^2 } \right ) \hat k


Option: 4

\left ( \frac{20y}{z} \right )\hat i+ \left ( \frac{20 x }{z } \right )\hat j - \left ( \frac{20 xy}{z^2 } \right ) \hat k


Answers (1)

best_answer

As we have learned

For Conservative Force field, force acting on the system -

f=\frac{-dU(x)}{dx}

- wherein

The negative of differentiation of  U\left ( x \right ) with respect to x.

 

 U = 20 xy/z 

F = - du/dr 

= -\frac{\delta u}{\delta x} \hat i - \frac{\delta u}{\delta y} \hat j - \frac{\delta u}{\delta z} \hat k

 = -\frac{20y}{z} \hat i - \frac{20x}{z} \hat j + \frac{20xy}{z^2} \hat k

 

Posted by

himanshu.meshram

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