The relation between the displacement x and the time t for a body of mass 2 kg moving under the action of force is given by x=t 3 /3 , where x is in metre and t in second , calculate the work done by body in first 2 seconds@gulamjilani shaikh
work done = change in kinetic energy
velocity v=dx/dt=t^2=4 for 2sec
W = .5mv^2=16J (since at t=0, v=0. so initial K.E=0)