# the temperature gradient in rod of 0.5m long is 80 degree centigrade per metre.if the temp.of hotter end of rod is 30 degree cntgrades,then the temperature of the colder end is? @vijay

$\frac{T_H-T_C}{L}=\frac{\Delta T}{L}$
$T_H-T_C=40\\T_C=-10$