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  • The Van der Waals constant b of Ar is <img alt="\small 3.22\times 10^-^5m^3\: mol^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cdpi%7B100%7D%20%5Csmall%203.22%5Ctimes%2010%5E-%5E5m%

The Van der Waals constant b of Ar is \small 3.22\times 10^-^5m^3\: mol^{-1} . Calculate the molecular diameter of Ar.

Option: 1

0.32nm


Option: 2

0.26nm


Option: 3

0.29nm


Option: 4

0.34nm


Answers (1)

best_answer

We know:
b = 4 x volume occupied by 1 mole of gas molecules.
Thus, we have:

b=4\times N_0 \times \left ( \frac{4}{3}\Pi r^3 \right )

3.22 \times 10^{-5}=4\times 6.023 \times 10^{23} \times \frac{4}{3} \times \frac{22}{7}\times r^3

r^3 =\left [\frac{3.22 \times 10^{-5} \times 3 \times 7}{4\times 6.023 \times 10^{23} \times 4 \times 22} \right ]^\frac{1}{3}

Thus, r = 0.147nm and d = 0.294
Therefore, Option(3) is correct

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