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Two capillary tubes A and B of equal radii \mathrm{r_a=r_b=} \mathrm{r} and equal lengths \mathrm{l_a=l_b=l} are held horizontally. When the same pressure difference P is maintained across each tube, the rate of flow of water in each is Q. If the tubes are connected in series and the same pressure difference P is maintained across the combination, the rate of flow through the combination will be

Option: 1

\mathrm{\frac{Q}{2}}


Option: 2

\mathrm{Q}


Option: 3

\mathrm{2 Q}


Option: 4

\mathrm{\frac{Q}{\sqrt{2}}}


Answers (1)

best_answer

A series combination of two identical capillary tubes, each of length l and radius r, is equivalent to a tube of length 2 l and radius r. Since Q is inversely proportional to l, if l is doubled, Q becomes half. Hence the correct choice is (a).

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