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Two circular coils 1 and 2 are made from the same wire but the radius of the 1st coil is twice that of die 2nd coil. What is the

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Q43 please n the approach behind these type of questions? Two circular coils 1 and 2 are made from the same wire but the radius of the 1st coil is twice that of die 2nd coil. What is the ratio of potential difference applied across them so that die magnetic field at their centres is the same
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Magnetic field due to circular coil at centre

B_{Centre}=\frac{\mu_{0}}{4\pi }\frac{2\pi Ni}{r}=\frac{\mu_{0} Ni}{2r}

given B1=B2

i_1/r_1 =i_2/r_2 \\given \ r_1=2r_2 \\ \ so\ i_1/i_2 =2

if R1 and R2 are resistance of the coil 1 and 2 then R1 = 2R2 (as R ∝ length )

so V1/V2 =4

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Safeer PP

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