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  • Two reaction of same order have equal exponential factors but their activation energy differ by <img alt="28.6 \mathrm{~K} \mathrm{Jm}^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?28.

Two reaction of same order have equal exponential factors but their activation energy differ by 28.6 \mathrm{~K} \mathrm{Jm}^{-1}. Calculate the ratio between the rate constant of the reaction at \mathrm{27^{\circ} \mathrm{C} .\left\{R=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right\}}

Option: 1

4.97


Option: 2

3.14


Option: 3

2.66


Option: 4

1.19


Answers (1)

best_answer

\mathrm{\begin{aligned} & \log k_1=\log A-\frac{E a}{R T} \\\\ & \log k_2=\log A-\frac{(E a+28.6)}{R T} \end{aligned}}

On doing Subtraction of both the rxn

\mathrm{\log \frac{k_2}{k_1}=\frac{28.6 \times 10^3}{2.303 \times 8.314 \times 300}=4.97}

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