# Two spherical bodies of mass M and 5 M and radii R and 2 R are released in free space with initial separation between their centres equal to 12 R If they attract each other dueto gravitational force only, then the distance covered by the smaller body before collision is:a) 7.5 Rc)25Rb) 1.5 Rd) 4.5 R

@sayali

their centre of mass will not change

apply this concept

have a look on this solution

As their centre of mass remains unchanged

$Mx_{1}=5Mx_{2}$   or  $x_{1}=5x_{2}$

$x_{1}+x_{2}=9R$

$x_{1}=7.5 R$

12R-3R=9R

appropriate ans?

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