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Water flows through a pipe bent at an angle \mathrm{\alpha} to the horizontal with a velocity \mathrm{ \mathrm{v}} . What is the force exerted by water on the bend of the pipe of area of cross section S ?

Option: 1

\mathrm{2 \rho v^2 S \sin \frac{\alpha}{2}}


Option: 2

\mathrm{2 \rho v^2 S \cos \alpha}


Option: 3

\mathrm{2 \rho v^2 S \sin \alpha}


Option: 4

\mathrm{2 \rho v^2 S \sin \alpha \cos \alpha}


Answers (1)

best_answer

 \mathrm{, \Delta v=2 v \sin \frac{a}{2}}

\mathrm{\mathrm{F}=\frac{\mathrm{m} \square \mathrm{v}}{\square \mathrm{t}}=(\rho \mathrm{sv})\left(2 \mathrm{v} \sin \frac{\mathrm{a}}{2}\right)}

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Anam Khan

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