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When a liquid in a glass vessel is heated its apparent expansion is 10.30\times 10^{-4}/_^{0}C . Same liquid when heated in a metal vessel its apparent expression is 10.06\times 10^{-4}/_^{0}C . The coefficient of linear expansion of the metal is \left (\alpha=9\times 10^{-6}/_^{0}\textrm{C} \right )
 

Option: 1

51\times 10^{-6}/_^{0}\textrm{C}

 

 

 


Option: 2

43\times 10^{-6}/_^{0}\textrm{C}


Option: 3

25\times 10^{-6}/_^{0}\textrm{C}


Option: 4

17\times 10^{-6}/_^{0}\textrm{C}


Answers (1)

best_answer

As we learned  

 

Co-efficient of Apparent Expansion -

\gamma_{a}=\frac{Apparent\ expansion\ in\ Volume}{Initial\ volume\times \Delta \theta}

\gamma_{a}=\frac{(\Delta v)_{a}}{V\times \Delta \theta}

-

 

 

r_{r}=r_{a}+r_{g}=r_{a}(in metal)+r_{m}

(in glass)

r_{m}=r_{a} (in glass) - r_{a}(in metal)+r_{g}

=(10.30-10.06)\times 10^{-4}+3\times 9\times 10^{-6}

=51\times 10^{-6}/_^{0}\textrm{C}

\alpha _{m}=17\times 10^{-6}/_^{0}\textrm{C}

Posted by

Pankaj Sanodiya

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