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  • When   is passed through acidified <img alt="\mathrm{K_2Cr_2O_7}" src="https://en

When \mathrm{SO_2}  is passed through acidified \mathrm{K_2Cr_2O_7} solution

Option: 1

the solution turns blue


Option: 2

the solution is decolourised


Option: 3

\mathrm{SO_2}  is reduced.


Option: 4

green \mathrm{Cr_2(SO_4)_3} is formed


Answers (1)

best_answer

\mathrm{K_2Cr_2O_7}  oxidises  \mathrm{SO_2} to  \mathrm{SO_4^{2-}} and itself converts into \mathrm{Cr^{3+}}. Finally green colored solution is obtained containing Cr(III) sulphate 

\mathrm{K_2Cr_2O_7+H_2SO_4+3SO_2\rightarrow K_2SO_4+\underset{Green}{Cr_2(SO_4)_3}+3H_2O}

Therefore, option (4) is correct.

Posted by

SANGALDEEP SINGH

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