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Which one of the following compound will form free radical easily ? 

Option: 1

\mathrm{CH_4}


Option: 2

\mathrm{(CH_3)_2CH_2}


Option: 3

\mathrm{(CH_3)_3 CH}


Option: 4

\mathrm{(CH_3CH_2 )_2CH_2}


Answers (1)

The greater the stability of the Free radical, the greater is its ease of formation.

In tertiary free radial, there are three methyl groups are present which has +I effect, which will stable the free radical more than others.

So, free radicals will easily form in a tertiary alkane.

Hence, the correct option is (3)

Posted by

Ramraj Saini

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