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NCERT Solutions for Class 11 Physics Chapter 10 Mechanical Properties of Fluids: If you're a Class 11 student in search of NCERT solutions, you're in the right spot. Here, on the Careers360 page, you can find extensive class 11 physics chapter 10 exercise solutions available for free, complete with detailed step-by-step explanations. This collection covers a total of thirty questions, including those from 10.1 to 10.20 for exercise questions and 10.20 to 10.30 for additional exercises.
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We all know that fluids do not have a particular shape. The shape of the fluid is decided by the shape of the container. In the solutions of NCERT Class 11 Physics Chapter 10 Mechanical Properties of Fluids, questions related to the properties of fluids (liquid and gas) and certain laws associated with the properties are discussed. Also, questions on all the topics of the chapter Mechanical Properties of Fluids Class 11 are covered in the CBSE NCERT solutions for Class 11 Physics Chapter 10 Mechanical Properties of Fluids and are very important from the exam point of view.
We all have heard the term pressure; Pascal's law is related to pressure and this law states that pressure in a fluid at rest is the same at all points which are at the same height. A change in pressure applied to an enclosed fluid is transmitted to every point of the fluid and the walls of the containing vessel container. One of the applications of this law is a Hydraulic Lift. Let's try to find a few more examples in NCERT by yourself. The main aim of the mechanical properties of fluids NCERT solutions is to check the depth of understanding of the concepts and formulas studied in the chapter. Careers360 has made the mechanical properties of fluids class 11 NCERT solutions available in PDF format, which can be accessed by students anytime and anywhere, to aid in their understanding of the chapter and its associated questions.
NCERT Class 11 Physics Chapter 10 Exercise Solutions PDF download for free.
**According to the CBSE Syllabus for the academic year 2023-24, the chapter you previously referred to as Chapter 10, " Mechanical Properties of Fluids ," has been renumbered as Chapter 9.
Q 10.1 (a) Explain why
The blood pressure in humans is greater at the fe et than at the brain
Answer:
The pressure in a fluid column increases with the height of the column, as the height of the blood column is more than that for the brain the blood pressure in feet is more than the blood pressure in the brain.
Q 10.1 (b) Explain why
Answer:
This is because the air density does not remain the same in the atmosphere. It decreases exponentially as height increases.
Q 10.1 (c) Explain why
Hydrostatic pressure is a scalar quantity even though pressure is force divided by area.
Answer:
When a force is applied on fluid the pressure which gets generated gets uniformly transmitted to all directions and therefore has no particular direction and is a scalar quantity. We talk of division of force with area only while considering the magnitudes. The actual vector form of the relation is
Q 10.2 (a) Explain why
(a) The angle of contact of mercury with glass is obtuse, while that of water with glass is acute.
Answer:
T SL = Surface tension corresponding to the solid-liquid layer
T LA = Surface tension corresponding to liquid-air layer
T SA = Surface tension corresponding to solid-air layer
The angle of contact is
Since the liquid is not flowing over the solid surface the components of T SL , T LA and T SA along the solid surface must cancel out each other.
In case of mercury T SA < T SL and therefore and therefore i.e the angle of contact of mercury with glass is obtuse.
Q 10.2 (b) Explain why
Answer:
Cohesive forces between water molecules is much lesser than adhesive forces between water and glass molecules and that's why water tends to spread out on glass whereas cohesive forces within mercury is comparable to adhesive forces between mercury and glass and that's why mercury tends to form drops.
Q 10.2 (c) Explain why
(c) Surface tension of a liquid is independent of the area of the surface
Answer:
Surface tension is the force acting per unit length at the interface of a liquid and another surface. Since this force itself is independent of area, the surface tension is also independent of area.
Q 10.2 (d) Explain why
(d) Water with detergent dissolved in it should have small angles of contact.
Answer:
As we know detergent with water rises very fast in capillaries of clothes which is only possible when cosine of the angle of contact is the large i.e. angle of contact must be small.
Q 10.2 (e) Explain why
(e) A drop of liquid under no external forces is always spherical in shape
Answer:
While in a spherical shape the surface area of the drop of liquid will be minimum and thus the surface energy would be minimum. A system always tends to be in a state of minimum energy and that's why in the absence of external forces a drop of liquid is always spherical in shape.
Q 10.3 Fill in the blanks using the word(s) from the list appended with each statement:
(a) Surface tension of liquids generally ... with temperatures (increases / decreases)
(b) Viscosity of gases ... with temperature, whereas viscosity of liquids ... with temperature (increases / decreases)
(c) For solids with elastic modulus of rigidity, the shearing force is proportional to ... , while for fluids it is proportional to ... (shear strain / rate of shear strain)
(d) For a fluid in a steady flow, the increase in flow speed at a constriction follows (conservation of mass / Bernoulli’s principle)
(e) For the model of a plane in a wind tunnel, turbulence occurs at a ... speed for turbulence for an actual plane (greater / smaller)
Answer:
(a) The surface tension of liquids generally decreases with temperatures.
(b) The viscosity of gases increases with temperature, whereas the viscosity of liquids decreases with temperature.
(c) For solids with elastic modulus of rigidity, the shearing force is proportional to shear strain , while for fluids it is proportional to the rate of shear strain .
(d) For a fluid in a steady flow, the increase in flow speed at a constriction follows from conservation of mass while the decrease of pressure there follows from Bernoulli’s principle .
(e) For the model of a plane in a wind tunnel, turbulence occurs at a greater speed for turbulence for an actual plane.
Q 10.4 (a) Explain why
(a) To keep a piece of paper horizontal, you should blow over, not under, it
Answer:
As per Bernoulli's principle when we blow over a piece of paper the pressure there decreases while the pressure under the piece of the paper remains the same and that's why it remains horizontal.
Q 10.4 (b) Explain why
Answer:
This is because when we cover the tap there are very small gaps remaining for the water to escape and it comes out at very high velocity in accordance with the equation of continuity.
Q 10.4 (c) Explain why
Answer:
Because of the extremely small size of the opening of a needle, its size can control the flow with more precision than the thumbs of a doctor.
According to the equation of continuity area * velocity= constant. if the area is very small the velocity must be large. Thus if the area is small flow becomes smooth
Q 10.4 (d) Explain why
(d) A fluid flowing out of a small hole in a vessel results in a backward thrust on the vessel
Answer:
Through a small area, velocity will be large. A fluid flowing out of a small hole in a vessel results in a backward thrust on the vessel in accordance with the law of conservation of linear momentum.
Q 10.4 (e) Explain why
(e) A spinning cricket ball in air does not follow a parabolic trajectory
Answer:
The ball while travelling rotates about its axis as well causing a difference in air velocities at different points around it thus creating pressure difference which results in external forces. In the absence of air, a ball would have travelled along the expected parabolic path.
Answer:
Mass of the girl m = 50 kg.
Gravitational acceleration g = 9.8 m s -2
Weight of the girl (W) , mg = 490 N
Answer:
Atmospheric pressure is
The density of French wine
Height of the wine column h w would be
Answer:
The density of water is
Depth of the ocean is 3 km
The pressure at the bottom of the ocean would be
The above value is much lesser than the maximum stress the structure can withstand and therefore it is suitable for putting up on top of an oil well in the ocean.
Answer:
Maximum Pressure which the piston would have to bear is
Answer:
Since the mercury columns in the two arms are equal the pressure exerted by the water and the spirit column must be the same.
Therefore the specific gravity of spirit is 0.8.
Answer:
Let the difference in the levels of mercury in the two arms be h Hg
Q 10.11 Can Bernoulli’s equation be used to describe the flow of water through a rapid in a river? Explain.
Answer:
No. Bernoulli's equation can be used only to describe streamline flow and the flow of water in a river is turbulent.
Answer:
No, unless the atmospheric pressures at the two points where Bernoulli’s equation is applied are significantly different.
Answer:
The volumetric flow rate of glycerine flow would be given by
The viscosity of glycerine is
Assuming Laminar flow for a tube of radius r, length l, having pressure difference P across its ends a fluid with viscosity would flow through it with a volumetric rate of
Reynolds number is given by
Since Reynolds Number is coming out to be 0.3 our Assumption of laminar flow was correct.
Answer:
The speed of air above and below the wings are given to be v 1 = 70 m s -1 and v 2 = 63 m s -1 respectively.
Let the pressure above and below the wings be p 1 and p 2 and let the model aeroplane be flying at a height h from the ground.
Applying Bernoulli's Principle on two points above and below the wings we get
The pressure difference between the regions below and above the wing is 605.15 Pa
The lift on the wing is F
Answer:
By the continuity equation, the velocity of the non-viscous liquid will be large at the kink than at the rest of the tube and therefore pressure would be lesser here by Bernoulli's principle and the air column above it, therefore, should be of lesser height. Figure (a) is therefore incorrect.
Answer:
Cross-sectional area of cylindrical tube is a 1 = 8.0 cm 2
The total area of the 40 fine holes is a 2
Speed of liquid inside the tube is v 1 = 1.5 m min -1
Let the speed of ejection of fluid through the holes be v 2
Using the continuity equation
Answer:
Total weight supported by the film
Since a soap film has two surfaces, the total length of the liquid film is 60 cm.
Surface Tension is T
Answer:
As the liquid and the temperature is the same in all three the surface tension will also be the same. Since the length is also given to be equal (40 cm) in all three cases the weight being supported is also the same and equal to .
Answer:
Surface Tension of Mercury is
The radius of the drop of Mercury is r = 3.00 mm
Excess pressure inside the Mercury drop is given by
Atmospheric Pressure is
Total Pressure inside the Mercury drop is given by
Answer:
Excess pressure inside a bubble is given by
(It's double the usual value because of the presence of 2 layers in case of soap bubble)
where T is surface tension and r is the radius of the bubble
Atmospheric Pressure is
The density of soap solution is
The pressure at a depth of 40 cm (h) in the soap solution is
Total Pressure inside an air bubble at that depth
Answer:
Pressure in the waterside at the bottom is
Pressure in the acid side at the bottom is
The pressure difference across the door is
Area of the door, a = 20 cm 2
The force necessary to keep the door closed is
Note: The dimensions of the door are small enough to neglect pressure variations near it.
(a) Give the absolute and gauge pressure of the gas in the enclosure for cases (a) and (b), in units of cm of mercury.
Answer:
In figure (a)
Gauge Pressure = 20 cm of Mercury
Absolute Pressure = Atmospheric Pressure + Gauge Pressure
Absolute Pressure = 76 + 20= 96 cm of Mercury
In figure (b)
Gauge Pressure = -18 cm of Mercury
Absolute Pressure = Atmospheric Pressure + Gauge Pressure
Absolute Pressure = 76 + (-18)= 58 cm of Mercury
(b) How would the levels change in case (b) if 13.6 cm of water (immiscible with mercury) are poured into the right limb of the manometer?
Answer:
As we know Specific Gravity of Mercury is 13.6 therefore 13.6 cm of water column would be equal to 1 cm of Mercury column.
The pressure at the Mercury Water interface in the right column = Atmospheric Pressure + 1 cm of Mercury = 77 cm of Mercury
The difference in Pressure due to the level of the Mercury column = Pressure at the Mercury Water interface - Absolute Pressure of the Glass enclosure
= 77 - 58 = 19 cm of Mercury.
The difference in the two limbs would, therefore, become 19 cm.
Answer:
Since the height of the water level in the vessels is the same the Pressure at the bottom would be equal. As the area of the bottom is also the same the Force exerted by the water on the bottom would be the same.
The difference in the reading arises due to the fact that the weight depends on the volume of the water inside the container which is more in the first vessel. The vertical component of the force exerted by the fluid on the sidewalls would be more in the first vessel and the difference in this vertical component is equal to the difference in the readings on a weighing scale.
Answer:
The density of whole blood
Gauge Pressure
Height at which the blood container must be placed so that blood may just enter the vein
(a) What is the largest average velocity of blood flow in an artery of diameter 2 × 10–3 m if the flow must remain laminar?
Answer:
The diameter of the artery is
The viscosity of blood is
The density of blood is
The average velocity is given by
Taking the Maximum value of Reynold's Number ( N Re = 2000) at which Laminar Flow takes place we have
(b) Do the dissipative forces become more important as the fluid velocity increases? Discuss qualitatively.
Answer:
As the fluid velocity increases the dissipative forces become important as turbulence rises due to which drag due to friction forces increases.
Answer:
The diameter of the artery is d
The viscosity of blood is
The density of blood is
The average velocity is given by
Taking the Maximum value of Reynold's Number ( N Re = 2000) at which Laminar Flow takes place we have
Q 10.26 (b) What is the corresponding flow rate? (Take viscosity of blood to be 2.084 × 10 -3 Pa s).
Answer:
Volumetric flow rate is given as
Answer:
Speed of the wind above the upper wing surface is v 1 = 234 km h -1
Speed of the wind over the lower wing is v 2 = 180 km h -1
Let the pressure over the upper and lower wing be P 1 and P 2
Let the plane be flying at a height of h
The density of air is
Applying Bernoulli's Principle at two points over the upper and lower wing we get
Area of each wing is a = 25 m 2
The net upward force on the plane is F
This upward force is equal to the weight m of the plane.
The mass of the plane is about 4400 kg
Answer:
Neglecting buoyancy due to air the terminal velocity is
Viscous Force F v at this speed is
Answer:
Since the angle of contact is obtuse the Pressure will be more on the Mercury side.
This pressure difference is given as
The dip of mercury inside the narrow tube would be equal to this pressure difference
The mercury dips down in the tube relative to the liquid surface outside by an amount of 5.34 mm.
Answer:
For the angle of contact , radius of the tube r, surface tension t, the density of fluid the rise in the column is given by
The radii of the two limbs r 1 and r 2 are 3.0 mm and 1.5 mm respectively
The level in the limb of diameter 6.0 mm is
The level in the limb of diameter 3.0 mm is
The difference in the heights is h 2 - h 1 = 4.96 mm
Providing class 11 physics chapter 10 exercise solutions is invaluable for Class 11 students, as it aids in their preparation. Additionally, understanding 'Mechanical Properties of Fluids' is crucial for competitive exams like JEE and NEET, where physics plays a significant role. This chapter of mechanical properties of fluids exercise equips students with essential knowledge about fluid behaviour under mechanical forces, helping them tackle complex questions in these exams with confidence.
NCERT Solutions for Class 11 Physics Chapter Wise
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | Mechanical Properties of Fluids |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
U = 1/2*strain*stress*volume
Where:
ΔQ is the amount of heat supplied to the substance and ΔT change in its temperature
These formulas are essential because they play a crucial role in solving problems and understanding the concepts covered in Chapter ch 10 physics class 11 ncert solutions.
Mechanical Properties Of Fluids Class 11 NCERT Physics Topics
The problems discussed in the NCERT solutions for Class 11 Physics chapter 10 Mechanical Properties of Fluids are based on the following topics.
10.1 Introduction
10.2 Pressure
10.3 Streamline flow
10.4 Bernoulli’s principle
10.5 Viscosity
10.6 Surface tension
The CBSE is widely recognized as the leading educational board in India, and it follows the NCERT Syllabus to administer examinations for both Class 10 and 12 students. The class 11 physics ch 10 ncert solutions, which focuses on Mechanical Properties of Fluids, have been provided to allow students to gain a comprehensive understanding of the concepts discussed in this chapter.
Fluids possess the fundamental property of being able to flow, and they lack resistance to alterations in their shape. Consequently, the shape of a fluid is determined by the shape of its container. The following are some important points about the Mechanical Properties of Fluids of Matter.
Comprehensive Coverage: The ch 10 physics class 11 ncert solutions cover all the topics and concepts presented in the chapter, ensuring a thorough understanding of mechanical properties of fluids.
Step-by-Step Solutions: Detailed step-by-step chapter 10 physics class 11 solutions for each exercise question are provided, making it easy for students to follow and grasp the concepts.
Clarity and Simplicity: The solutions are explained in clear and simple language, making complex concepts easy to understand.
Diagrams and Graphs: Wherever necessary, diagrams and graphs are included to enhance visual understanding and clarify concepts related to fluid properties.
Concise Summaries: NCERT solutions often include concise summaries of the main points in each section, helping students revise and retain important information.
Examination-Oriented: The ch 10 physics class 11 are designed to help students prepare for exams, including CBSE board exams and various competitive exams that may include questions related to fluid mechanics.
Yes, the topics studied are the basics of fluid dynamics which is mainly studied in mechanical and civil related branches.
On an average one question is asked from the chapter Mechanical Properties of Fluids for both JEE Main and NEET exam. It can be morethan one also. All the formulas given in the NCERT book for Mechanical Properties of Fluids chapter are important. To get more problems related to the formulas students can use NCERT exemplar and JEE main and NEET previous year papers.
The subtopic covered in mechanical properties of fluids are give below:
1. Introduction
2. Pressure
3. Streamline flow
4. Bernoulli’s principle
5. Viscosity
6. Surface tension
To solve the questions given in physics class 11 chapter 10, you can follow these steps:
Read the question carefully and understand what is being asked.
Identify the concept or formula required to solve the question.
Make sure you understand the formula and its variables.
Substitute the given values in the formula and solve for the unknown variable.
Check your answer and make sure it is reasonable and accurate.
Practice similar problems to improve your understanding and speed.
Chapter 10 notes of Physics Class 11 are important for JEE and NEET exams as they cover fundamental concepts related to fluid mechanics. Understanding these concepts can help students solve questions and excel in related fields of engineering.
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Depending on the video game designer job description and experience they may also have to lead a team and do the early testing of the game in order to suggest changes and find loopholes.
Radio Jockey is an exciting, promising career and a great challenge for music lovers. If you are really interested in a career as radio jockey, then it is very important for an RJ to have an automatic, fun, and friendly personality. If you want to get a job done in this field, a strong command of the language and a good voice are always good things. Apart from this, in order to be a good radio jockey, you will also listen to good radio jockeys so that you can understand their style and later make your own by practicing.
A career as radio jockey has a lot to offer to deserving candidates. If you want to know more about a career as radio jockey, and how to become a radio jockey then continue reading the article.
The word “choreography" actually comes from Greek words that mean “dance writing." Individuals who opt for a career as a choreographer create and direct original dances, in addition to developing interpretations of existing dances. A Choreographer dances and utilises his or her creativity in other aspects of dance performance. For example, he or she may work with the music director to select music or collaborate with other famous choreographers to enhance such performance elements as lighting, costume and set design.
A career as social media manager involves implementing the company’s or brand’s marketing plan across all social media channels. Social media managers help in building or improving a brand’s or a company’s website traffic, build brand awareness, create and implement marketing and brand strategy. Social media managers are key to important social communication as well.
Photography is considered both a science and an art, an artistic means of expression in which the camera replaces the pen. In a career as a photographer, an individual is hired to capture the moments of public and private events, such as press conferences or weddings, or may also work inside a studio, where people go to get their picture clicked. Photography is divided into many streams each generating numerous career opportunities in photography. With the boom in advertising, media, and the fashion industry, photography has emerged as a lucrative and thrilling career option for many Indian youths.
An individual who is pursuing a career as a producer is responsible for managing the business aspects of production. They are involved in each aspect of production from its inception to deception. Famous movie producers review the script, recommend changes and visualise the story.
They are responsible for overseeing the finance involved in the project and distributing the film for broadcasting on various platforms. A career as a producer is quite fulfilling as well as exhaustive in terms of playing different roles in order for a production to be successful. Famous movie producers are responsible for hiring creative and technical personnel on contract basis.
In a career as a copywriter, one has to consult with the client and understand the brief well. A career as a copywriter has a lot to offer to deserving candidates. Several new mediums of advertising are opening therefore making it a lucrative career choice. Students can pursue various copywriter courses such as Journalism, Advertising, Marketing Management. Here, we have discussed how to become a freelance copywriter, copywriter career path, how to become a copywriter in India, and copywriting career outlook.
In a career as a vlogger, one generally works for himself or herself. However, once an individual has gained viewership there are several brands and companies that approach them for paid collaboration. It is one of those fields where an individual can earn well while following his or her passion.
Ever since internet costs got reduced the viewership for these types of content has increased on a large scale. Therefore, a career as a vlogger has a lot to offer. If you want to know more about the Vlogger eligibility, roles and responsibilities then continue reading the article.
For publishing books, newspapers, magazines and digital material, editorial and commercial strategies are set by publishers. Individuals in publishing career paths make choices about the markets their businesses will reach and the type of content that their audience will be served. Individuals in book publisher careers collaborate with editorial staff, designers, authors, and freelance contributors who develop and manage the creation of content.
Careers in journalism are filled with excitement as well as responsibilities. One cannot afford to miss out on the details. As it is the small details that provide insights into a story. Depending on those insights a journalist goes about writing a news article. A journalism career can be stressful at times but if you are someone who is passionate about it then it is the right choice for you. If you want to know more about the media field and journalist career then continue reading this article.
Individuals in the editor career path is an unsung hero of the news industry who polishes the language of the news stories provided by stringers, reporters, copywriters and content writers and also news agencies. Individuals who opt for a career as an editor make it more persuasive, concise and clear for readers. In this article, we will discuss the details of the editor's career path such as how to become an editor in India, editor salary in India and editor skills and qualities.
Individuals who opt for a career as a reporter may often be at work on national holidays and festivities. He or she pitches various story ideas and covers news stories in risky situations. Students can pursue a BMC (Bachelor of Mass Communication), B.M.M. (Bachelor of Mass Media), or MAJMC (MA in Journalism and Mass Communication) to become a reporter. While we sit at home reporters travel to locations to collect information that carries a news value.
Are you searching for a Corporate Executive job description? A Corporate Executive role comes with administrative duties. He or she provides support to the leadership of the organisation. A Corporate Executive fulfils the business purpose and ensures its financial stability. In this article, we are going to discuss how to become corporate executive.
A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.
Welding Engineer Job Description: A Welding Engineer work involves managing welding projects and supervising welding teams. He or she is responsible for reviewing welding procedures, processes and documentation. A career as Welding Engineer involves conducting failure analyses and causes on welding issues.
A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.
A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
A QA Lead is in charge of the QA Team. The role of QA Lead comes with the responsibility of assessing services and products in order to determine that he or she meets the quality standards. He or she develops, implements and manages test plans.
A Structural Engineer designs buildings, bridges, and other related structures. He or she analyzes the structures and makes sure the structures are strong enough to be used by the people. A career as a Structural Engineer requires working in the construction process. It comes under the civil engineering discipline. A Structure Engineer creates structural models with the help of computer-aided design software.
The Process Development Engineers design, implement, manufacture, mine, and other production systems using technical knowledge and expertise in the industry. They use computer modeling software to test technologies and machinery. An individual who is opting career as Process Development Engineer is responsible for developing cost-effective and efficient processes. They also monitor the production process and ensure it functions smoothly and efficiently.
An AWS Solution Architect is someone who specializes in developing and implementing cloud computing systems. He or she has a good understanding of the various aspects of cloud computing and can confidently deploy and manage their systems. He or she troubleshoots the issues and evaluates the risk from the third party.
An Azure Administrator is a professional responsible for implementing, monitoring, and maintaining Azure Solutions. He or she manages cloud infrastructure service instances and various cloud servers as well as sets up public and private cloud systems.
Careers in computer programming primarily refer to the systematic act of writing code and moreover include wider computer science areas. The word 'programmer' or 'coder' has entered into practice with the growing number of newly self-taught tech enthusiasts. Computer programming careers involve the use of designs created by software developers and engineers and transforming them into commands that can be implemented by computers. These commands result in regular usage of social media sites, word-processing applications and browsers.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
Individuals in the information security manager career path involves in overseeing and controlling all aspects of computer security. The IT security manager job description includes planning and carrying out security measures to protect the business data and information from corruption, theft, unauthorised access, and deliberate attack
An Automation Test Engineer job involves executing automated test scripts. He or she identifies the project’s problems and troubleshoots them. The role involves documenting the defect using management tools. He or she works with the application team in order to resolve any issues arising during the testing process.
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