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NCERT Solutions for Class 12 Physics Chapter 3 Current Electricity - Welcome to the updated current electricity class 12 exercise solutions for one of the easy and intriguing chapters in the Class 12 syllabus. On this page, you will discover comprehensive NCERT solutions spanning from question 3.1 to 3.23. Questions 3.1 to 3.14 are part of the exercise section, while the rest are from the additional exercise. These class 12 physics chapter 3 ncert solutions have been meticulously crafted by subject experts, aligning with the latest syllabus and offering detailed explanations.
Physics Class 12 chapter 3 NCERT solutions are related to Ohm’s law and Kirchoff's law which will help in solving circuit related problems in exams. The NCERT Solutions for Class 12 Physics Chapter 3 also explains problems related to heat developed in a resistor. The basics of these chapters are covered in NCERT of high school classes also.
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Current is the flow of electric charge through a given area. If we want to utilize the charge flow, we must have a closed path. NCERT Solutions For Class 12 Physics chapter 3 explains questions about the factors affecting the current flow, how current flows in a conductor, basic laws related to current electricity and circuit analysis and a few measuring devices. NCERT Solutions for Class 12 contain the answer to each question given in NCERT Class 12 Physics book.
Free download class 12 physics chapter 3 exercise solutions PDF for CBSE exam.
Given, the emf of battery, E = 12 V
Internal resistance of battery, r = 0.4 Ohm
Let I be the maximum current drawn from the battery.
We know, according to Ohm's law
E = Ir
I = E/r = 12/0.4 =30 A
Hence the maximum current drawn from the battery is 30 A.
Given, The emf of the battery, E = 10 V
The internal resistance of the battery, r = 3 Ohm
Current in the circuit, I = 0.5 A
Let R be the resistance of the resistor.
Therefore, according to Ohm's law:
E = IR' = I(R + r)
10 = 0.5(R + 3)
R = 1 Ohm
Also,
V = IR (Across the resistor)
= 0.5 x 17 = 8.5 V
Hence, terminal voltage across the resistor = 8.5 V
We know that when resistors are combined in series, the effective resistance is the sum of that resistance.
Hence, total resistance of the three resistance combination = 1 + 2 + 3 = 6 Ohm
Answer:
Since the resistances are in series, the current through each one of them will be equal to the current through the circuit but voltage/ potential drop will be different.
Total resistance, R = 6 Ω
Emf, V = 12 V
According to Ohm's law:
V = IR
12 = I x 6
I = 12/6 = 2 A
Now, using the same relation, voltage through resistors:
1 Ω : V(1) = 2 x 1 = 2V
2 Ω : V(2) = 2 x 2 = 4V
3 Ω : V(3) = 2 x 3 = 6V
(Note: V(1) + V(2) + V(3) = 2 + 4 + 6 = 12 V )
We know that when resistances are in parallel combination, the total resistance R is given by:
Therefore, total resistance of the given three resistances in parallel combination is
Hence, the total resistance is 1.05 Ω
Since the resistances are in parallel, the voltage across each one of them will be equal.
Emf, V = 20 V
According to Ohm's law:
V = IR I = V/R
Therefore, current across each one of them is:
2 Ω : I = 20/2 = 10 A
4 Ω : I = 20/4 = 5 A
5 Ω : I = 20/5 = 4 A
Given,
temperature coefficient of filament,
α = 1.7 x 10-4 oC-1
;
Let T2 be the temperature of element, R2=117 Ω
(Positive alpha means that the resistance increases with temperature. Hence we can deduce that T2 will be greater than T1 )
We know,
Hence, the temperature of the element is 1027 °C.
, where is the resistivity of the material
Hence, the resistivity of the material of wire is
3.7 A silver wire has a resistance of 2.1 Ω at 27.5 °C, and a resistance of 2.7 Ω at 100 °C. Determine the temperature coefficient of resistivity of silver.
Given,
;
;
We know,
2.7 = 2.1[1 + (100 - 27.5) ]
= (2.7 - 2.1) / 2.1(100 -27.5)
= 0.0039
Hence, the temperature coefficient of silver wire is 0.0039
For the given voltage, the two values of current will correspond to two different values of resistance which will correspond to two different temperature.
V = 230 V
and
Using Ohm's law:
and
Let be the steady temperature of the heating element.
We know,
That is
230/2.8 = 230/3.2[1 + ( ) ( T 2 - 27) ]
T 2 = (840.5 + 27) °C
Hence, steady temperature of the element is 867.5 °C .
3.9 Determine the current in each branch of the network shown in Fig. 3.30:
Answer:
Let current in the circuit is distributed like
where I1, I2, and I3 are the different current through shown branches.
Now, applying KVL in Loop
Also, we have
so putting it in kvl equation
.................................(1)
Now let's apply kvl in the loop involving I1 I2 AND I3
.................................(2)
now, the third equation of KVL
..............................(3)
Now we have 3 equation and 3 variable, on solving we get
Now the total current
Balance point from the end A, l 1 = 39.5 cm
Resistance of Y = 12.5 Ω
We know, for a meter bridge, balance condition is:
The connections between resistors in a Wheatstone or meter bridge made of thick copper strips to minimise the resistance of the connection which is not accounted for in the bridge formula.
(b) Determine the balance point of the bridge above if X and Y are interchanged.
If X and Y are interchanged.
Then, X = 12.5 Ω , Y = 8.2 Ω
We know, for a meter bridge, balance condition is:
if the galvanometer and cell are interchanged the galvanometer will show no current and hence no deflection.
Emf of battery, E = 8 V
Internal resistance of battery, r = 0.5 Ω
Supply Voltage, V = 120 V
The resistance of the resistor, R = 15.5 Ω
Let V' be the effective voltage in the circuit.
Now, V' = V - E
V' = 120 - 8 = 112 V
Now, current flowing in the circuit is:
I = V' / (R + r)
Now, using Ohm ’s Law:
Voltage across resistor R is v = IR
V = 7 x 15.5 = 108.5 V
Now, the voltage supplied, V = Terminal voltage of battery + V
Terminal voltage of battery = 120 -108.5 = 11.5 V
The purpose of having a series resistor is to limit the current drawn from the supply.
Let E2 be the voltage in the second case.
Now, the balance condition is given by :
Therefore, the emf of the second cell = 2.25 V
We know,
vd :drift Velocity = length of wire(l) / time taken to cover
by substituting the given values
t = 2.7 x 104 s
Therefore, the time required by an electron to drift from one end of a wire to its other end is s.
Given, the surface charge density of earth
=
Current over the entire globe = 1800 A
Radius of earth, r = 6.37 x 106 m
The surface area of earth A =
= =
Now, charge on the earth surface,
Therefore,
Let the time taken to neutralize earth surface be t
Current I = q / t
t = 282.78 s.
Therefore, time take to neutralize the Earth's surface is 282.78 s
Given,
There are 6 secondary cells.
Emf of each cell, E = 2 V (In series)
The internal resistance of each cell, r = 0.015 Ω (In series)
And the resistance of the resistor, R = 8.5 Ω
Let I be the current drawn in the circuit.
I = 1.4 A
Hence current drawn from the supply is 1.4 A
Therefore, terminal voltage, V = IR = 1.4 x 8.5 = 11.9 V
Given,
Emf , E = 1.9 V
Internal resistance, r =380 Ω
The maximum current that can drawn is I = E/r = 1.9/380 = 0.005 A
The motor requires a large value of current to start and hence this cell cannot be used for a motor of a car.
We know,
R = Ρ l / A
The wires have the same resistance and also are of the same length.
Hence,
Now, mass = Density x Volume = Density x Area x length
Taking the ratio of their masses for the same length
Hence,
Therefore, for the same resistance and length, the aluminium wire is lighter.
Since aluminium wire is lighter, it is used as power cables.
3.17 What conclusion can you draw from the following observations on a resistor made of alloy manganin?
Current A | Voltage V | Current A | Voltage V |
---|---|---|---|
0.2 | 3.94 | 3.0 | 59.2 |
0.4 | 7.87 | 4.0 | 78.8 |
0.6 | 11.8 | 5.0 | 98.6 |
0.8 | 15.7 | 6.0 | 118.5 |
1.0 | 19.7 | 7.0 | 138.2 |
2.0 | 39.4 | 8.0 | 158.0 |
The ratio of Voltage to current for the various values comes out to be nearly constant which is around 19.7.
Hence the resistor made of alloy manganin follows Ohm's law.
Answer the following questions:
The current flowing through the conductor is constant for a steady current flow.
Also, current density, electric field, and drift speed are inversely proportional to the area of cross-section. Hence, not constant.
Answer the following questions:
No. Ohm’s law is not universally applicable for all conducting elements.
A semiconductor diode is such an example.
Answer the following questions
3.18 (c) A low voltage supply from which one needs high currents must have very low internal resistance. Why?
Ohm's law states that: V = I x R
Hence for a low voltage V, resistance R must be very low for a high value of current.
Answer the following questions:
3.18 (d) A high tension (HT) supply of, say, 6 kV must have a very large internal resistance. Why?
A very high internal resistance is required for a high tension supply to limit the current drawn for safety purposes.
3.19 Choose the correct alternative:
(a) Alloys of metals usually have (greater/less) resistivity than that of their constituent metals.
(b) Alloys usually have much (lower/higher) temperature coefficients of resistance than pure metals.
(c) The resistivity of the alloy manganin is nearly independent of/ increases rapidly with increase of temperature.
(d) The resistivity of a typical insulator (e.g., amber) is greater than that of a metal by a factor of the order of ( ).
(a) Alloys of metals usually have greater resistivity than that of their constituent metals.
(b) Alloys usually have much lower temperature coefficients of resistance than pure metals.
(c) The resistivity of the alloy manganin is nearly independent of temperature.
(d) The resistivity of a typical insulator (e.g., amber) is greater than that of a metal by a factor of the order of 1022 .
3.20 (a)
To get maximum effective resistance, combine them in series. The effective resistance will be nR.
3.20 (a)
To get minimum effective resistance, combine them in parallel. The effective resistance will be R/n.
3.20 (a)
(iii) What is the ratio of the maximum to minimum resistance?
The ratio is nR/(R/n) =
3.20 (b)
We have, equivalent resistance = 11/3
Let's break this algebraically so that we can represent it in terms of 1, 2 and 3
this expression is expressed in terms of 1, 2 and 3. and hence we can make a circuit which consist only of 1 ohm, 2 ohms and 3 ohms and whose equivalent resistance is 11/3. that is :
3.20 (b)
Connect 2 Ω and 3 Ω resistor in parallel and 1 Ω resistor in series to it
Equivalent Resistance R = {1/(1/2 + 1/3)} + 1 = 6/5 + 1
R = 11/5 Ω
3.20 (b)
1 Ω+2 Ω+ 3 Ω= 6 Ω, so we will combine the resistance in series.
3.20 (b)
Connect all three resistors in parallel.
Equivalent resistance is R = 1/(1/1 + 1/2 + 1/3) = (1x 2 x 3)/(6 + 3 + 2)
R = 6/11 Ω
3.20 (c)
(a) Determine the equivalent resistance of networks shown in
Fig. 3.31.
It can be seen that in every small loop resistor 1 ohm is in series with another 1 ohm resistor and two 2 ohms are also in series and we have 4 loops,
so equivalent resistance of one loop is equal to the parallel combination of 2 ohms and 4 ohm that is
now we have 4 such loops in series so,
Hence equivalent resistance of the circuit is 16/3 ohm.
3.20 (c)
(b) Determine the equivalent resistance of networks shown in Fig. 3.31.
It can be seen that all 5 resistors are in series, so
Equivalent Resistance = R + R + R + R + R = 5R
Hence equivalent resistance is 5R.
Answer:
First, let us find the equivalent of the infinite network,
let equivalent resistance = R'
Here from the figure, We can consider the box as a resistance of R'
Now, we can write,
equivalent resistance = R'
' =[( R')Parallel with (1)] + 1 + 1
Since resistance can never be negative we accept
, We have calculated the equivalent resistance of infinite network,
Now
Total equivalent resistance = internal resistance of battery+ equivalent resistance of the infinite network
= 0.5+1+1.73
=3.23 ohm
Hence current drawn from the 12V battery is 3.72 Ampere.
Given
maintained constant emf of standard cell = 1.02V, balanced point of this cell = 67.3cm
Now when the standard cell is replaced by another cell with emf = . balanced point for this cell = 82.3cm
Now as we know the relation
hence emf of another cell is 1.247V.
(b) What purpose does the high resistance of 600 k have?
If a sufficiently high current passes through galvanometer then it can get damaged. So we limit the current by adding a high resistance of 600 k .
(c) Is the balance point affected by this high resistance?
No, the Balance point is not affected by high resistance. High resistance limits the current to galvanometer wire. The balance point is obtained by moving the joe key on the potentiometer wire and current through potentiometer wire is constant. The balance point is the point when the current through galvanometer becomes zero. The only duty of high resistance is to supply limited constant current to potentiometer wire.
No, the method would not have worked if the driver cell of the potentiometer had an emf of 1.0V instead of 2, because when emf of the driving point is less than the other cell, their won't be any balance point in the wire
(e) Would the circuit work well for determining an extremely small emf, say of the order of a few mV (such as the typical emf of a thermo-couple)? If not, how will you modify the circuit?
No, the circuit would not work properly for very low order of Voltage because the balance points would be near point A and there will be more percentage error in measuring it. If we add series resistance with wire AB. It will increase the potential difference of wire AB which will lead to a decrease in percentage error.
3.23 Figure 3.34 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Ω is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell.
Answer:
Given,
the balance point of cell in open circuit =
value of external resistance added =
new balance point =
let the internal resistance of the cell be .
Now as we know, in a potentiometer,
hence the internal resistance of the cell will be 1.68
Chapter 3 physics class 12 ncert solutions are essential for students preparing for board exams, JEE, and NEET. This chapter covers basic concepts like electric current and resistance. Understanding these concepts is important for board exams and helps in competitive exams like JEE and NEET. Class 12 current electricity ncert solutions also forms the foundation for advanced studies in physics and electrical engineering. So, it's a key chapter for success in exams and future studies.
Where: is the angle between the normal to the area and direction of current
Relation between current density and electric field
where = conductivity and = resistivity or specific resistance of the substance
Where:
m is the mass, n is the number of electrons per unit volume, e is the charge of the electron and is the relaxation time
Grouping of Resistance
Series Grouping of resistance
Parallel Grouping of Resistance
Heat developed in a resistor
(Balanced condition)
Current Electricity Class 12 solutions for exercise questions are important from the board as well as competitive exam point of view. Following are the main topics covered in ch3 Physics Class 12.
Electric current- The concept of electric current, drift velocity, mobility etc are covered in the first part of the NCERT chapter on current electricity. All the formulas and concepts in the NCERT Class 12 Physics are important for the CBSE board exam and questions based on these parts are covered in the Current Electricity Class 12 NCERT solutions
Ohms law- Ohms law gives a linear relationship between voltage and current at a given temperature. And also discuss that not all conductors obey ohms law. There are ohmic and non-ohmic conductors. From here the term resistance is introduced and the questions related to this law is discussed in the NCERT Solutions for Class 12 Physics Chapter 3.
Resistance and Resistivity-The concepts of resistance and resistivity are discussed here. The variations of resistance and resistivity with temperature and colour code of resistance are discussed in chapter 3 Physics Class 12. Questions related to this are discussed in current electricity NCERT solutions.
Cells and their combinations-The concepts of cells, their series and parallel combinations are discussed in the CBSE Class 12 chapter 3 Current Electricity.
Kirchoff's law-This section discusses two important laws used to solve circuits namely Kirchoff's current law and voltage law. This part is important as far as competitive exams are concerned.
Wheatstone's bridge, meter bridge and potentiometer- The concepts of Wheatstone's bridge and meter bridge along with their balanced condition are discussed here. Meter bridge is an application of balanced Wheatstone's bridge. The concept of the potentiometer and its applications to compare EMFs of cells and also to find the internal resistance of cells are discussed in the chapter on current electricity. The questions from this part have high weightage for NEET and JEE main exams. 1 question from this part can be expected for JEE Main and NEET. To practice questions on this refer to chapter 3 Physics Class 12 NCERT Solutions.
As far as the CBSE board exam and competitive exams are considered, the solutions of NCERT Class 12 Physics chapter 3 are important. In NEET and JEE Main previous year papers, 7 to 10% questions are asked from this chapter. In CBSE board exam 2019, 6 marks questions are asked from current electricity. Use these CBSE NCERT solutions for Class 12 Physics chapter 3 PDF for a better score in board and competitive exams.
This NCERT Solutions for Class 12 Physics chapter 3 will help in practising questions for annual exams.
Students can solve and match their answers from this Class 12 Physics Chapter 3 NCERT solutions.
These current electricity Class 12 NCERT solutions will give proper answers that will help students in exams to score good marks.
In case of any doubt, while solving any question given in chapter 3 Physics Class 12, students can refer to this solution to know how to solve the questions and what is the answer to a question.
Comprehensive Coverage: These class 12 current electricity ncert solutions cover all the topics and questions presented in Chapter 3, ensuring a thorough understanding of "Current Electricity."
Detailed Explanations: Each solution provides step-by-step explanations, making complex concepts more accessible to students.
Clarity and Simplicity: The current electricity class 12 exercise solutions are written in clear and simple language, aiding students in better comprehension.
Practice Questions: Exercise questions are included, allowing students to practice and self-assess their understanding.
Preparation for Exams: These class 12 physics chapter 3 ncert solutions help students prepare effectively for board exams, JEE, NEET, and other competitive exams.
Foundation for Future Studies: The concepts covered in this chapter are essential for advanced topics in physics and electrical engineering.
Interconnected Concepts: It establishes connections to later chapters, emphasizing its importance as a foundational chapter.
Free Access: These solutions are available for free, making them easily accessible to all students.
These features make NCERT Class 12 Physics Chapter 3 Solutions a valuable resource for students to excel in their studies and exams.
Also, check
Excluded Content:
Certain portions of Chapter 3, "Current Electricity," have been omitted:
In CBSE board exam, around 8 to 10% questions can be expected from the chapter Current Electricity. Certain papers of CBSE ask around 15% questions from NCERT chapter 3 Current Electricity. To score well in the exam follow NCERT syllabus and the exercise given in the NCERT Book. To practice more problems can refer to NCERT exemplar.
If we analyse the previous year NEET, JEE Main and board papers we can see that the topics like meter bridge, potentiometer and problems using kcl and kvl and combinations of resistance and cells are frequently asked.
In JEE main, 2 to 3 questions can be expected from the chapter on Current Electricity. The topics like Potentiometer, meter bridge, KVL and KCL are important.
The concepts in the current electricity chapter of NCERT Class 12 Physics are integral parts of NEET exam. Along with NCERT, practicing with previous year papers and mock tests would be enough.
Current electricity carries 8% of weightage on an average for NEET exam.
Current electricity is the basics of electrical and electronics engineering-related branches. In these branches, analysis and designs of the circuit are important and the basic laws studied in the Class 12 Physics Chapter 3 NCERT solutions help for the same.
The main topics are-
hello,
Yes you can appear for the compartment paper again since CBSE gives three chances to a candidate to clear his/her exams so you still have two more attempts. However, you can appear for your improvement paper for all subjects but you cannot appear for the ones in which you have failed.
I hope this was helpful!
Good Luck
Hello dear,
If you was not able to clear 1st compartment and now you giving second compartment so YES, you can go for your improvement exam next year but if a student receives an improvement, they are given the opportunity to retake the boards as a private candidate the following year, but there are some requirements. First, the student must pass all of their subjects; if they received a compartment in any subject, they must then pass the compartment exam before being eligible for the improvement.
As you can registered yourself as private candidate for giving your improvement exam of 12 standard CBSE(Central Board of Secondary Education).For that you have to wait for a whole year which is bit difficult for you.
Positive side of waiting for whole year is you have a whole year to preparing yourself for your examination. You have no distraction or something which may causes your failure in the exams. In whole year you have to stay focused on your 12 standard examination for doing well in it. By this you get a highest marks as a comparison of others.
Believe in Yourself! You can make anything happen
All the very best.
Hello Student,
I appreciate your Interest in education. See the improvement is not restricted to one subject or multiple subjects and we cannot say if improvement in one subject in one year leads to improvement in more subjects in coming year.
You just need to have a revision of all subjects what you have completed in the school. have a revision and practice of subjects and concepts helps you better.
All the best.
If you'll do hard work then by hard work of 6 months you can achieve your goal but you have to start studying for it dont waste your time its a very important year so please dont waste it otherwise you'll regret.
Yes, you can take admission in class 12th privately there are many colleges in which you can give 12th privately.
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Individuals who opt for a career as an environmental engineer are construction professionals who utilise the skills and knowledge of biology, soil science, chemistry and the concept of engineering to design and develop projects that serve as solutions to various environmental problems.
A Naval Architect is a professional who designs, produces and repairs safe and sea-worthy surfaces or underwater structures. A Naval Architect stays involved in creating and designing ships, ferries, submarines and yachts with implementation of various principles such as gravity, ideal hull form, buoyancy and stability.
Orthotists and Prosthetists are professionals who provide aid to patients with disabilities. They fix them to artificial limbs (prosthetics) and help them to regain stability. There are times when people lose their limbs in an accident. In some other occasions, they are born without a limb or orthopaedic impairment. Orthotists and prosthetists play a crucial role in their lives with fixing them to assistive devices and provide mobility.
A career in pathology in India is filled with several responsibilities as it is a medical branch and affects human lives. The demand for pathologists has been increasing over the past few years as people are getting more aware of different diseases. Not only that, but an increase in population and lifestyle changes have also contributed to the increase in a pathologist’s demand. The pathology careers provide an extremely huge number of opportunities and if you want to be a part of the medical field you can consider being a pathologist. If you want to know more about a career in pathology in India then continue reading this article.
Gynaecology can be defined as the study of the female body. The job outlook for gynaecology is excellent since there is evergreen demand for one because of their responsibility of dealing with not only women’s health but also fertility and pregnancy issues. Although most women prefer to have a women obstetrician gynaecologist as their doctor, men also explore a career as a gynaecologist and there are ample amounts of male doctors in the field who are gynaecologists and aid women during delivery and childbirth.
An oncologist is a specialised doctor responsible for providing medical care to patients diagnosed with cancer. He or she uses several therapies to control the cancer and its effect on the human body such as chemotherapy, immunotherapy, radiation therapy and biopsy. An oncologist designs a treatment plan based on a pathology report after diagnosing the type of cancer and where it is spreading inside the body.
The audiologist career involves audiology professionals who are responsible to treat hearing loss and proactively preventing the relevant damage. Individuals who opt for a career as an audiologist use various testing strategies with the aim to determine if someone has a normal sensitivity to sounds or not. After the identification of hearing loss, a hearing doctor is required to determine which sections of the hearing are affected, to what extent they are affected, and where the wound causing the hearing loss is found. As soon as the hearing loss is identified, the patients are provided with recommendations for interventions and rehabilitation such as hearing aids, cochlear implants, and appropriate medical referrals. While audiology is a branch of science that studies and researches hearing, balance, and related disorders.
The hospital Administrator is in charge of organising and supervising the daily operations of medical services and facilities. This organising includes managing of organisation’s staff and its members in service, budgets, service reports, departmental reporting and taking reminders of patient care and services.
For an individual who opts for a career as an actor, the primary responsibility is to completely speak to the character he or she is playing and to persuade the crowd that the character is genuine by connecting with them and bringing them into the story. This applies to significant roles and littler parts, as all roles join to make an effective creation. Here in this article, we will discuss how to become an actor in India, actor exams, actor salary in India, and actor jobs.
Individuals who opt for a career as acrobats create and direct original routines for themselves, in addition to developing interpretations of existing routines. The work of circus acrobats can be seen in a variety of performance settings, including circus, reality shows, sports events like the Olympics, movies and commercials. Individuals who opt for a career as acrobats must be prepared to face rejections and intermittent periods of work. The creativity of acrobats may extend to other aspects of the performance. For example, acrobats in the circus may work with gym trainers, celebrities or collaborate with other professionals to enhance such performance elements as costume and or maybe at the teaching end of the career.
Career as a video game designer is filled with excitement as well as responsibilities. A video game designer is someone who is involved in the process of creating a game from day one. He or she is responsible for fulfilling duties like designing the character of the game, the several levels involved, plot, art and similar other elements. Individuals who opt for a career as a video game designer may also write the codes for the game using different programming languages.
Depending on the video game designer job description and experience they may also have to lead a team and do the early testing of the game in order to suggest changes and find loopholes.
Radio Jockey is an exciting, promising career and a great challenge for music lovers. If you are really interested in a career as radio jockey, then it is very important for an RJ to have an automatic, fun, and friendly personality. If you want to get a job done in this field, a strong command of the language and a good voice are always good things. Apart from this, in order to be a good radio jockey, you will also listen to good radio jockeys so that you can understand their style and later make your own by practicing.
A career as radio jockey has a lot to offer to deserving candidates. If you want to know more about a career as radio jockey, and how to become a radio jockey then continue reading the article.
The word “choreography" actually comes from Greek words that mean “dance writing." Individuals who opt for a career as a choreographer create and direct original dances, in addition to developing interpretations of existing dances. A Choreographer dances and utilises his or her creativity in other aspects of dance performance. For example, he or she may work with the music director to select music or collaborate with other famous choreographers to enhance such performance elements as lighting, costume and set design.
A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.
A career as social media manager involves implementing the company’s or brand’s marketing plan across all social media channels. Social media managers help in building or improving a brand’s or a company’s website traffic, build brand awareness, create and implement marketing and brand strategy. Social media managers are key to important social communication as well.
In a career as a copywriter, one has to consult with the client and understand the brief well. A career as a copywriter has a lot to offer to deserving candidates. Several new mediums of advertising are opening therefore making it a lucrative career choice. Students can pursue various copywriter courses such as Journalism, Advertising, Marketing Management. Here, we have discussed how to become a freelance copywriter, copywriter career path, how to become a copywriter in India, and copywriting career outlook.
Careers in journalism are filled with excitement as well as responsibilities. One cannot afford to miss out on the details. As it is the small details that provide insights into a story. Depending on those insights a journalist goes about writing a news article. A journalism career can be stressful at times but if you are someone who is passionate about it then it is the right choice for you. If you want to know more about the media field and journalist career then continue reading this article.
For publishing books, newspapers, magazines and digital material, editorial and commercial strategies are set by publishers. Individuals in publishing career paths make choices about the markets their businesses will reach and the type of content that their audience will be served. Individuals in book publisher careers collaborate with editorial staff, designers, authors, and freelance contributors who develop and manage the creation of content.
In a career as a vlogger, one generally works for himself or herself. However, once an individual has gained viewership there are several brands and companies that approach them for paid collaboration. It is one of those fields where an individual can earn well while following his or her passion.
Ever since internet costs got reduced the viewership for these types of content has increased on a large scale. Therefore, a career as a vlogger has a lot to offer. If you want to know more about the Vlogger eligibility, roles and responsibilities then continue reading the article.
Individuals in the editor career path is an unsung hero of the news industry who polishes the language of the news stories provided by stringers, reporters, copywriters and content writers and also news agencies. Individuals who opt for a career as an editor make it more persuasive, concise and clear for readers. In this article, we will discuss the details of the editor's career path such as how to become an editor in India, editor salary in India and editor skills and qualities.
Linguistic meaning is related to language or Linguistics which is the study of languages. A career as a linguistic meaning, a profession that is based on the scientific study of language, and it's a very broad field with many specialities. Famous linguists work in academia, researching and teaching different areas of language, such as phonetics (sounds), syntax (word order) and semantics (meaning).
Other researchers focus on specialities like computational linguistics, which seeks to better match human and computer language capacities, or applied linguistics, which is concerned with improving language education. Still, others work as language experts for the government, advertising companies, dictionary publishers and various other private enterprises. Some might work from home as freelance linguists. Philologist, phonologist, and dialectician are some of Linguist synonym. Linguists can study French, German, Italian.
The career of a travel journalist is full of passion, excitement and responsibility. Journalism as a career could be challenging at times, but if you're someone who has been genuinely enthusiastic about all this, then it is the best decision for you. Travel journalism jobs are all about insightful, artfully written, informative narratives designed to cover the travel industry. Travel Journalist is someone who explores, gathers and presents information as a news article.
Welding Engineer Job Description: A Welding Engineer work involves managing welding projects and supervising welding teams. He or she is responsible for reviewing welding procedures, processes and documentation. A career as Welding Engineer involves conducting failure analyses and causes on welding issues.
A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.
A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
A QA Lead is in charge of the QA Team. The role of QA Lead comes with the responsibility of assessing services and products in order to determine that he or she meets the quality standards. He or she develops, implements and manages test plans.
A metallurgical engineer is a professional who studies and produces materials that bring power to our world. He or she extracts metals from ores and rocks and transforms them into alloys, high-purity metals and other materials used in developing infrastructure, transportation and healthcare equipment.
An Azure Administrator is a professional responsible for implementing, monitoring, and maintaining Azure Solutions. He or she manages cloud infrastructure service instances and various cloud servers as well as sets up public and private cloud systems.
An AWS Solution Architect is someone who specializes in developing and implementing cloud computing systems. He or she has a good understanding of the various aspects of cloud computing and can confidently deploy and manage their systems. He or she troubleshoots the issues and evaluates the risk from the third party.
Careers in computer programming primarily refer to the systematic act of writing code and moreover include wider computer science areas. The word 'programmer' or 'coder' has entered into practice with the growing number of newly self-taught tech enthusiasts. Computer programming careers involve the use of designs created by software developers and engineers and transforming them into commands that can be implemented by computers. These commands result in regular usage of social media sites, word-processing applications and browsers.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
Individuals in the information security manager career path involves in overseeing and controlling all aspects of computer security. The IT security manager job description includes planning and carrying out security measures to protect the business data and information from corruption, theft, unauthorised access, and deliberate attack
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