NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers Numbers are very important for real life as well as for mathematics. In the previous classes, you have learnt to work with numbers. In the first chapter, you will deal with the number systems and some basic operations of numbers. You have added, subtracted, divided and multiplied them. This chapter will move forward on interesting things like patterns in number sequences with a brief review and revision as well. CBSE NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers is also there to provide you assistance in solving the practice problems. In NCERT class 6 maths chapter 1 Knowing Our Numbers, you will learn Indian arrangement of numeration, the universal arrangement of numeration, learn large numbers up to 1 crore ( 10000000 ), estimation of large numbers and roman numerals. Along with all these, you will also learn how to write and read these large numbers, comparing numbers for example which number is greatest and which number is the smallest among the given numbers. CBSE NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers are covering the solutions for the problems from all the concepts. In this particular chapter, there is a total of 19 questions in 3 exercises. Solutions of NCERT for class 6 maths chapter 1 Knowing Our Numbers are covering all the problems' solutions in a very comprehensive manner. Apart from this chapter, you can check the NCERT solutions for other classes and subjects using the given link.
3. 1834, 75284, 111, 2333, 450
4. 2853, 7691, 9999, 12002, 124
Answer:
By Observing the number of digits and digit in the leftmost place can straight away tell us about the greatest and smallest number
(2) 1473, 89423, 100, 5000, 310
89423 is the greatest while 100 is the smallest
(3) 1834, 75284, 111, 2333, 450
75284 is the greatest 111 while is the smallest
(4) 2853, 7691, 9999, 12002, 124
12002 is the greatest while 124 is the smallest
Answer:
(a) 4536, 4892, 4370, 4452
4892 is the greatest while 4370 is the smallest
(b) 15623, 15073, 15189, 15800
15800 is the greatest while 15073 is the smallest
(c) 25286, 25245, 25270, 25210
25286 is the greatest while 25245 is the smallest
(d) 6895, 23787, 24569, 24659
24659 is the greatest while 6895 is the smallest
NCERT solutions for class 6 maths chapter 1 Knowing our numbers Topic: Number Formation
Answer:
(a) 2, 8, 7, 4
8742 is the greatest while 2478 is the smallest
(b) 9, 7, 4, 1
9741 is the greatest 1479 while is the smallest
(c) 4, 7, 5, 0
4750 is the greatest while 4057 is the smallest
(d) 1, 7, 6, 2
7621 is the greatest while 1267 is the smallest
(e) 5, 4, 0, 3
5430 is the greatest while 3045 is the smallest
Answer:
(a) 3, 8, 7
8873 is the greatest while 3387 is the smallest
(b) 9, 0, 5
9950 is the greatest while 5009 is the smallest
(c) 0, 4, 9
9940 is the greatest while 4009 is the smallest
(d) 8, 5, 1
8851 is the greatest while 1158 is the smallest
Q3 Make the greatest and the smallest 4digit numbers using any four different digits with conditions as given.
(a) Digit 7 is always at one's place
Greatest  9 8 6 7
Smallest  1 0 2 7
(Note, the number cannot begin with the digit 0. Why?)
(b) Digit 4 is always at tens place
Greatest  _ _ 4 _
Smallest  _ _ 4 _
(c) Digit 9 is always at hundreds place
Greatest  _ 9 _ _
Smallest  _ 9 _ _
(d) Digit 1 is always at thousands place
Greatest 1 _ _ _
Smallest  1 _ _ _
Answer:
(b) Digit 4 is always at tens place
Greatest  9847
Smallest  1042
(c) Digit 9 is always at hundreds place
Greatest  8976
Smallest  1902
(d) Digit 1 is always at thousands place
Greatest 1987
Smallest  1023
Answer:
Greatest number  3322
Smallest number  2233
Different numbers are
2222, 2232, 2233, 2322, 2333, 2332, 2323, 2223, 3222, 3223, 3232, 3233, 3322, 3333, 3332, 3323
There are 16 in total
NCERT solutions for class 6 maths chapter 1 Knowing our numbers Topic: Arrangement of Numbers
Answer:
(a) 847, 8320, 8320, 571
571 < 847 < 8320 < 8320
(b) 9801, 25751, 25751, 38802
9801 < 25751 < 25751 < 38802
Answer:
(a) 5000, 7500, 85400, 7861
85400 > 7861 > 5000 > 75000
(b) 1971, 45321, 88715
88715 > 45321 > 1971
Solutions of NCERT for class 6 maths chapter 1 Knowing our numbers Topic: Revisiting Place Value
Q1 Read and expand the numbers wherever there are blanks.
5. 29485________________________________________
6. 29085________________________________________
Answer:
1. 50000Fifty thousand
2. 41000forty one thousand
3. 47300 fortyseven thousand and three hundred
4. 57630 fiftyseven thousand six hundred
5. 29485 twentynine thousand and four hundred eightyfive
6. 29085 twentyNine Thousand and EightyFive
Q2 Read and expand the numbers wherever there are blanks.
4,57,928 _______________ _______________
4,07,928 _______________ _______________
4,00,829 _______________ _______________
4,00,029 _______________ _______________
Answer:
4,57,928 Four Lakhs Fifty Seven Thousand and Nine Hundred Twenty Eight
4,07,928 Four Lakhs Seven Thousand and Nine Hundred TwentyEight
4,00,829 Four Lakhs Eight Hundred TwentyNine
4,00,029 Four Lakhs and TwentyNine
Q3 You have the following digits 4, 5, 6, 0, 7 and 8.
Using them, make five numbers each with 6 digits.
(a) Put commas for easy reading.
(b) Arrange them in ascending and descending order.
Answer:
Given, digits :
Five 6digit numbers are:
(a) 1 lakh = _______ ten thousand.
(b) 1 million = _______ hundred thousand.
(c) 1 crore = _______ ten lakh.
(d) 1 crore = _______ million.
Answer:
Let us take this as a physical world problem:
You went to a shop and you bought a toy of Rs. 100. You checked your pocket and found many notes but of only Rs.10
How many Rs.10 notes will you give to shopkeeper:
Well, it’s simple.
You will pay 10 notes.
How?
100/10 =10
The similar easy approach can be done in all the blanks,
Hint: Always remember to keep your eyes on a number of zeros
(a)1 lakh= 100000
1thousand= 1000
Ten thousand= 10*1000 = 10000
Therefore,
1 lakh/ 10 thousand =100000/10000 =10
So, 1lakh= 10 ten thousand
(b) 1 million= 1000000
1thousand= 1000
Hundred thousand= 100*1000 = 100000
Therefore,
1 million/ hundred thousand =1000000/100000 =10
So, 1milion= 10 hundred thousand
(c) 1 crore= 10000000 (7 zeros)
1lakh= 100000 (5 zeros)
Ten lakh= 10*1000 = 1000000( 6 zeros)
Therefore,
1 crore/ Ten lakh=10000000/1000000 =10
So, 1 crore= 10 Ten lakh
(d)1 crore= 10000000 (7 zeros)
1million= 100000 (6 zeros)
Therefore,
1 crore/ 1million=10000000/1000000 =10
So, 1 crore= 10 million
(e) 1 million= 1000000
1lakh= 100000
Therefore,
1million/ 10 lakh = 1000000/100000 =10
So, 1 million= 10 lakhs
See, all answers came out to be 10 but not everytime
Q2 Place commas correctly and write the numerals:
(a) Seventy three lakh seventy five thousand three hundred seven.
(b) Nine crore five lakh forty one.
(c) Seven crore fifty two lakh twenty one thousand three hundred two.
(d) Fifty eight million four hundred twenty three thousand two hundred two.
(e) Twenty three lakh thirty thousand ten.
Answer:
(a) Seventy three lakh seventy five thousand three hundred seven.
(b) Nine crore five lakh forty one.
(c) Seven crore fifty two lakh twenty one thousand three hundred two.
(d) Fifty eight million four hundred twenty three thousand two hundred two.
(e) Twenty three lakh thirty thousand ten.
Q3 Insert commas suitably and write the names according to Indian System of Numeration :
(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701
Answer:
(a) : Eight crores seventy five lakhs ninety five thousand seven hundred sixty two
(b) : Eighty five lakhs forty six thousand two hundred eighty three.
(c) : Nine crores ninety nine lakhs and forty six.
(d) : Nine crores eighty four lakhs thirty two thousand seven hundred and one.
Answer:
Number of medicine tablets =
Weight of each medicine tablet =
Therefore, total weight =
Answer:
(i) Total distance from A to D = AB + BC + CD
(ii) Total distance between D to G = DE + EF + FG
(iii) Required distance = AD + DG + GA
(iv) The difference of distances from C to D and D to E
NCERT solutions for class 6 maths chapter 1 Knowing our numbers Excercise: 1.2
Answer:
Given,
Tickets sold on the first day of exhibition = 1094
Tickets sold on the second day = 1812
Tickets sold on the third day = 2050
Tickets sold on the last day = 2751
Total number of tickets sold =
Total number of tickets sold =
Answer:
The number of runs scored by Shekhar so far = 6980
The number of runs Shekhar wishes to score = 10,000
The number of runs required =
Therefore, Shekhar requires .
Answer:
Given,
Number of votes registered by the successful candidate = 5, 77,500 votes
Number of votes registered by the rival candidate = 3, 48,700 votes
The margin
Therefore, the successful candidate won the election by a margin of votes.
Answer:
Given,
Worth of books sold in the first week =
Worth of books sold in the second week =
Total sale in the two weeks =
Clearly, sales in the second week is greater than the first year by
Answer:
Given, digits: 6, 2, 7, 4 and 3
Since, the digits have to be used only once, arrange them in ascending and descending order to get the minimum and maximum number.
Greatest number =
Smallest number =
The difference between the greatest and the least number
Answer:
Given,
Screws produced by machine in one day =
We know, there are 31 days in January
Screws produced in 31 days =
Therefore, screws produced in January 2006 =
Answer:
Total money merchant has =
Cost of one radio set =
Cost of 40 radio sets =
Money left with the merchant =
Therefore, money left with her after purchase =
Answer:
Given,
The student multiplied instead of .
Wrong answer =
Correct answer =
The difference in the answers =
Hence, his answer was greater than the correct answer by
Answer:
We know,
Given,
Length of cloth required to stitch a shirt =
Also,
Now, the cloth required for one shirt =
Number of shirts that can be stitched out =
Therefore, 18 shirts can be made from the given cloth.
And, cloth will remain unused.
Answer:
We know,
Weight of each medicine box=
Weight limit of the van =
The number of boxes that can be loaded in the van =
Hence, 177 boxes can be loaded in the van.
Answer:
We know,
Given,
Distance between the school and her house =
The distance she covers each day =
Therefore, she will cover in six days.
Answer:
We know,
Given, Capacity of vessel =
The capacity of a single glass =
Number of glasses required to fill the vessel =
Hence, 180 glasses are needed to fill the vessel completely.
Answer:
Given Number 
Approximate to Nearest 
Rounded Form 
75847 
Tens 

75847 
Hundreds 

75847 
Thousands 

75847 
Ten thousands 

NCERT solutions for class 6 maths chapter 1 Knowing our numbers Excercise: 1.3
Answer:
(a)
By rounding off to hundreds,
730 rounds off to 700,
998 rounds off to 1000.
Required sum =
(b)
By rounding off to hundreds,
796 rounds off to 800,
314 rounds off to 300.
Required difference =
(c)
By rounding off to thousands,
2904 rounds off to 13000,
2822 rounds off to 3000.
Required sum =
(d)
By rounding off to nearest thousands,
28,296 rounds off to 28000,
21,496 rounds off to 21,000
Required difference =
Answer:
(a)
Rounding off to nearest hundreds,
439 rounds off to 400
334 rounds off to 300
4317 rounds off to 4300,
Required sum =
Again, by rounding off to nearest tens,
439 rounds off to 440
334 rounds off to 330
4317 rounds off to 4320,
Required sum =
(b)
Rounding off to nearest hundreds,
rounds off to
rounds off to
Required difference =
Also, rounding off to nearest tens,
rounds off to
rounds off to
Required difference =
(c)
Rounding off to nearest hundreds,
8325 rounds off to 8300
491 rounds off to 500
Required difference =
Also, rounding off to nearest tens,
8325 rounds off to 8330
491 rounds off to 490
Required difference =
(d)
Rounding off to nearest hundreds,
rounds off to
rounds off to
Required difference =
Also, rounding off to nearest tens,
rounds off to
rounds off to
Required difference =
Answer:
(a)
Rounding off by general rule,
578 rounds off to 600
161 rounds off to 200,
Required product =
(b)
Rounding off by the general rule,
5281 rounds off to 5000
3491 rounds off to 3500
Required product =
(c)
Rounding off by general rule,
1291 rounds off to 1300
592 rounds off to 600
Required product =
(d)
Rounding off by general rule,
9250 rounds off to 10000
29 rounds off to 30Required product =
Answer:
(a) Four multiplied by the sum of nine and two.
(b) Divide the difference of eighteen and six by four.
(c) Fortyfive divided by three times the sum of three and two.
Chapters No. 
Chapters Name 
Chapter  1 
NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers 
Chapter  2 
Solutions of NCERT for class 6 maths chapter 2 Whole Numbers 
Chapter  3 
CBSE NCERT solutions for class 6 maths chapter 3 Playing with Numbers 
Chapter  4 
NCERT solutions for class 6 maths chapter 4 Basic Geometrical Ideas 
Chapter  5 
Solutions of NCERT for class 6 maths chapter 5 Understanding Elementary Shapes 
Chapter  6 

Chapter  7 

Chapter  8 

Chapter  9 
CBSE NCERT solutions for class 6 maths chapter 9 Data Handling 
Chapter 10 

Chapter 11 

Chapter 12 
CBSE NCERT solutions for class 6 maths chapter 12 Ratio and Proportion 
Chapter 13 

Chapter 14 
Solutions of NCERT for class 6 maths chapter 14 Practical Geometry 
Keep working hard and happy learning!
1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Q. A bus started its journey and reached different places with a speed of 60 km/hour.
(i) Find the total distance covered by the bus from A to D.
(ii) Find the total distance covered by the bus from D to G.
(iii) Find the total distance covered by the bus, if it starts from A and returns back to A.
(iv) Can you find the difference of distances from C to D and D to E?
2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?