NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers

NCERT solutions for class 6 maths chapter 2 Whole Numbers- This chapter is a part of the number system unit. It will specifically deal with the whole numbers. The whole number is a new topic and it is important to learn also. It starts with the introduction of whole numbers and revision of natural numbers and then goes on with discussions of the predecessor and successor of whole numbers and natural numbers. CBSE NCERT solutions for class 6 maths chapter 2 Whole Numbers are covering the solutions for the questions from every concept. The other important topics of this chapter are a representation of whole numbers in the number line, properties of whole numbers and patterns in whole numbers. Before coming to this chapter you must ensure that you are comfortable with the natural numbers. The natural numbers are the numbers 1, 2, 3, 4, 5... which you use for counting. The natural numbers along with zero forms the collection of the whole numbers. CBSE NCERT solutions for class 6 maths chapter 2 Whole Numbers are covering in-depth solutions to every problem related to the whole numbers. In this particular chapter, there are 3 exercises containing 38 questions. Solutions of NCERT for class 6 maths chapter 2 Whole Numbers contains all the 38 problems' solution to make your preparation better. Along with all these, you can click on the link given to get NCERT solutions for other classes and subjects.

The solutions for following exercise are given

Exercise 2.1

Exercise 2.2

Exercise 2.3

NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Predecessor and Successor

Q1 Write the predecessor and successor of 19; 1997; 12000; 49; 100000.

Answer:

The predecessor and successor are:

19:

Predecessor : 18

Successor : 20

1997:

Predecessor : 1996

Successor : 1998

12000

Predecessor : 11999

Successor : 12001

49:

Predecessor : 48

Successor : 50

100000:

Predecessor : 99999

Successor : 100001

Q2 Is there any natural number that has no predecessor?

Answer:

Every natural number has a predecessor.

Although it is interesting to know that the predecessor of 1 is not a natural number.

Q3 Is there any natural number which has no successor? Is there a last natural number?

Answer:

Every natural number has a successor. There is no last natural number. There are infinite natural numbers.

NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Whole Numbers

Q1 Are all natural numbers also whole numbers?

Answer:

Yes, all natural numbers are whole numbers.

But, all whole numbers are not natural numbers.

Natural numbers = $1, 2, 3, 4, .....$

Whole numbers= $\mathbf{0},1,2,3,4, ....$

Q2 Are all whole numbers also natural numbers?

Answer:

No, all whole numbers are not natural numbers.

0 is a whole number, but it is not a natural number.

Q3 Which is the greatest whole number?

Answer:

There are infinite whole numbers. Hence, there is no greatest whole number.

Every whole number you can think of has a successor, which is greater than than the number.

Solutions for NCERT class 6 maths chapter 2 Whole Numbers Exercise: 2.1

Q1 Write the next three natural numbers after 10999.

Answer:

Given, $10999$

The next three natural numbers are:

$10999+1= 11000$

$10999+2= 11001$

$10999+3= 11002$

Q2 Write the three whole numbers occurring just before 10001.

Answer:

Given,

$10001$

Three whole numbers occurring just before are:

$10001-1 = 10000$

$10001-2 = 9999$

$10001-3 = 9998$

Q3 Which is the smallest whole number?

Answer:

The smallest whole number is 0. It has no whole number predecessor.

Q4 How many whole numbers are there between 32 and 53?

Answer:

Given numbers are : $32\ and\ 53$

Number of whole numbers between $32\ and\ 53$ = $(53-32)-1= 21-1 = 20$

There are $20$ whole numbers between $32\ and\ 53$

Q5 Write the successor of :
(a) 2440701 (b) 100199 (c) 1099999 (d) 2345670

Answer:

The successor of following numbers are:

(a) 2440701

$2440701+1 = 2440702$

(b) 100199

$100199 +1 = 100200$

$1099999+1 = 1100000$

(d) 2345670

$2345670+1 = 2345671$

Q6 Write the predecessor of :
(a) 94 (b) 10000 (c) 208090 (d) 7654321

Answer:

The predecessor of the following numbers are:

(a) 94

$94-1=93$

(b) 10000

$10000 -1=9999$

$208090 -1=208089$

(d) 7654321

$7654321-1=7654320$

Q7 In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them.
(a) 530, 503 (b) 370, 307 (c) 98765, 56789 (d) 9830415, 10023001

Answer:

The number on the left on the number line is smaller than the number that is on the right on the number line.

(a) 530, 503

$503$ is on the left.

$\therefore 530 > 503$

(b) 370, 307

$307$ is on the left.

$\therefore 370> 307$

$56789$ is on the left.

$\therefore 98765> 56789$

(d) 9830415, 10023001

$9830415$ is on the left.

$\therefore 9830415< 10023001$

Q8 Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number

Answer:

(a) Zero is the smallest natural number. - False. 0 is not a natural number.
(b) 400 is the predecessor of 399. - False. 400 is the successor of 399.
(c) Zero is the smallest whole number. - True.
(d) 600 is the successor of 599. - True
(e) All natural numbers are the whole numbers.- True.
(f) All whole numbers are natural numbers.-False. 0 is a whole number but not a natural number.
(g) The predecessor of a two-digit number is never a single-digit number.- False. The predecessor of 10 is 9.
(h) 1 is the smallest whole number. - False. 0 is the smallest whole number.
(i) The natural number 1 has no predecessor. - True.
(j) The whole number 1 has no predecessor. - False. The whole number 1 has 0 as its predecessor.
(k) The whole number 13 lies between 11 and 12.- False. The whole number 13 lies on the right side of 12 on the number line.
(l) The whole number 0 has no predecessor.- True.
(m) The successor of a two-digit number is always a two-digit number- False. The successor of 99 is 100.

NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Properties of Whole Numbers

Q Find : 7 + 18 + 13; 16 + 12 + 4.

Answer:

7 + 18 + 13; 16 + 12 + 4

NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.2

Q1 Find the sum by suitable rearrangement:
(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647

Answer:

Sum by suitable rearrangement:

(a) 837 + 208 + 363

$837 + 208 + 363 =837 + 363+ 208$

$= (837 + 363)+ 208$

$= 1200 + 208$

$= 1408$

(b) 1962 + 453 + 1538 + 647

$1962 + 453 + 1538 + 647 = 1962+ 1538 + 453 + 647$

$= (1962+ 1538) + (453 + 647)$

$= 3500 + 1100$

$= 4600$

Q2 Find the product by suitable rearrangement:
(a) 2 × 1768 × 50 (b) 4 × 166 × 25
(c) 8 × 291 × 125 (d) 625 × 279 × 16
(e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25

Answer:

The product of the following by suitable rearrangement are:

(a) $2 \times 1768 \times 50$

$\\ = 2 \times 50\times 1768 \\ = (2 \times 50)\times 1768 \\ = 100\times 1768 \\ = 176800$

(b) $4 \times 166 \times 25$

$\\ = 4\times 25 \times 166 \\ = (4\times 25 )\times 166 \\ = 100 \times 166 \\ = 16600$

$\\ = 8 \times125 \times 291 \\ =( 8 \times125) \times 291 \\ = 1000\times 291 \\ = 291000$

(d) $625 \times 279 \times 16$

$\\ = 625 \times 16\times 279 \\ = (625 \times 16)\times 279 \\ = 10000\times 279 \\ = 2790000$

(e) $285 \times 5 \times 60$

$\\ = 285 \times (5 \times 60) \\ = 285 \times 300 \\ = 85500$

(f) $125 \times 40 \times 8 \times 25$

$\\ = 125\times 8 \times 40 \times 25 \\ = (125\times 8 )\times (40 \times 25) \\ = 1000 \times 1000 \\ = 1000000$

Q3 Find the value of the following:
(a) 297 × 17 + 297 × 3 (b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69 (d) 3845 × 5 × 782 + 769 × 25 × 218

Answer:

(a) $297 \times 17 + 297 \times 3$

Using Distributive law.

$\\ = 297 \times (17 +3) \\ = 297 \times 20 \\ = 5940$

(b) $54279 \times 92 + 8 \times 54279$

Using Commutative under multiplication

$54279 \times 92 + 54279 \times 8$

Using Distributive law.

$\\ = 54279 \times( 92 +8) \\ = 54279 \times 100 \\ = 5427900$

Using Distributive law.

$\\ = 81265 \times (169 - 69) \\ = 81265 \times 100 \\ = 8126500$

(d) $3845 \times 5 \times 782 + 769 \times 25 \times 218$

$\\ = (3845 \times 5) \times 782 + (769 \times 25) \times 218 \\ = 19225 \times 782 + 19225\times 218$

Using distributive law.

$\\ = 19225 \times( 782 + 218) \\ = 19225 \times1000 \\ = 19225000$

Q4 Find the product using suitable properties.
(a) 738 × 103 (b) 854 × 102
(c) 258 × 1008 (d) 1005 × 168

Answer:

The product of the folllowing using suitable properties are:

(a) $738 \times 103$

$\\ = 738 \times (100+3)$

Using distributive law.

$\\ = 738 \times 100+738 \times3 \\ = 73800+2214 \\ = 76014$

(b) $854 \times 102$

$\\ = 854 \times (100+2)$

Using distributive law.

$\\ = 854 \times 100+854 \times 2 \\ = 85400+1708 \\ = 87108$

$\\ = 258 \times (1000+8)$

Using Distributive law.

$\\ = 258 \times 1000+258 \times8 \\ = 258000+2064 \\ = 260064$

(d) $1005 \times 168$

$\\ = (1000+5) \times 168$

Using Distributive law.

$\\ = 1000\times 168+5 \times 168 \\ = 168000+840 \\ = 168840$

Q5 A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs rupees 44 per litre, how much did he spend in all on petrol?

Answer:

Amount of petrol filled on Monday = $40\ litres$

Amount of petrol filled on Tuesday = $40\ litres$

$\therefore$ Total amount of petrol = $(40+40)\ litres = 80\ litres$

Cost of 1 litre of petrol = $Rs.\ 44$

$\therefore$ Cost of $80\ litres$ of petrol = $Rs.\ (44\times80)$

$= Rs.\ 3520$

Q6 A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs rupees 45 per litre, how much money is due to the vendor per day?

Answer:

Amount of milk supplied in the morning = $32\ litres$

Amount of milk supplied in the evening = $68\ litres$

$\therefore$ Total amount of petrol = $(32+68)\ litres = 100\ litres$

Cost of 1 litre of milk = $Rs.\ 45$

$\therefore$ Cost of $100\ litres$ of milk = $Rs.\ (45\times100)$

$= Rs.\ 4500$

Q7 Match the following:
(i) 425 × 136 = 425 × (6 + 30 +100) (a) Commutativity under multiplication.
(ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition.

Answer:

(i) $425 \times 136 = 425 \times (6 + 30 +100)$	(c) Distributivity of multiplication over addition.
(ii) $2 \times 49 \times 50 = 2 \times 50 \times 49$	(a) Commutativity under multiplication.
(iii) $80 + 2005 + 20 = 80 + 20 + 2005$	(b) Commutativity under addition.

NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Patterns in Whole Numbers

Q1 Which numbers can be shown only as a line?

Answer:

$1,5,7,11,13$ can be shown only as a line.

They cannot be shown as rectangle or square or triangle.

Q2 Which can be shown as squares?

Answer:

$4$ and $9$ can be shown as squares.

4: 2 rows and 2 columns.

9: 3 rows and 3 columns

Q3 Which can be shown as rectangles?

Answer:

$4, 6, 8,10, 12$ can be shown as rectangles.

(Note: We are not counting squares as recatangles here)

Q4 Write down the first seven numbers that can be arranged as triangles, e.g. 3, 6, ...

Answer:

3, 6, 10, 15, 21, 28, 36.

Q5 Some numbers can be shown by two rectangles, for example

Give at least five other such examples.

Answer:

We can represent a number by two rectangles. for example 12 = 3 x 4 or 2 x 6

five other such examples are :

24 = 12 x 2 or 24 = 6 x 4

18 = 9 x 2 or 18 = 3 x 6

15 = 15 x 1 or 15 = 3 x 5

30 = 10 x 3 or 30 = 5 x 6

40 = 10 x 4 or 40 = 5 x 8.

NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.3

Q1 Which of the following will not represent zero:
(a) 1 + 0 (b) 0 × 0 (c) 0/ 2 (d) (10-10)/2

Answer:

(a) 1 + 0

It does not represent zero.

(b) 0 × 0

It represents zero.

(c)

$\frac{0}{2}=0$

It represents zero.

(d)

$\frac{10-10}{2}=0$

It represents zero.

Q2 If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

Answer:

If the product of 2 whole numbers is zero, then one of them is definitely zero.

For example,

0 x 2 = 0 and 17 x 0 = 0

If the product of 2 whole numbers is zero, then both of them may be zero.

0 x 0 = 0

However, 2 x 3 = 6 (Since numbers to be multiplied are not equal to zero, the result of the product will also be non-zero.)

Q3 If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.

Answer:

If the product of 2 numbers is 1, then both the numbers have to equal to 1.

For example, 1 x 1 = 1

However, 1 x 6 = 6

Clearly, the product of two whole numbers will be 1 in the situation when both numbers to be multiplied are 1.

Q4 Find using distributive property :
(a) 728 $\times$ 101 (b) 5437 $\times$ 1001 (c) 824 $\times$ 25 (d) 4275 $\times$ 125 (e) 504 $\times$ 35

Answer:

(a) 728 $\times$ 101= 728 $\times$ (100 + 1)

= 728 $\times$ 100 + 728 $\times$ 1

= 72800 + 728

= 73528

(b) 5437 $\times$ 1001 = 5437 $\times$ (1000 + 1)

= 5437 $\times$ 1000 + 5437 $\times$ 1

= 5437000 + 5437

= 5442437

=800 $\times$ 25+25 x 25-1 $\times$ 25

= 20000 + 625 - 25

= 20000 + 600

= 20600

(d) 4275 $\times$ 125 = (4000 + 200 + 100 - 25) $\times$ 125

= 4000 $\times$ 125 + 200 $\times$ 125 + 100 $\times$ 125 - 25 $\times$ 125

= 500000 + 25000 + 12500 - 3125

= 534375

(e) 504 $\times$ 35 = (500 + 4) $\times$ 35

= 500 x 35 +4 $\times$ 35

= 17500 + 140

= 17640

Q5 Study the pattern :
1 $\times$ 8 + 1 = 9 1234 $\times$ 8 + 4 = 9876
12 $\times$ 8 + 2 = 98 12345 $\times$ 8 + 5 = 98765
123 $\times$ 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).

Answer:

123456 $\times$ 8 + 6 = 987648 + 6 = 987654

1234567 $\times$ 8 + 7 = 9876536 + 7 = 9876543

Yes, the pattern works.

As 123456 = 111111 + 11111 + 1111 + 111 + 11 + 1,

123456 $\times$ 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) $\times$ 8

= 111111 $\times$ 8 + 11111 $\times$ 8 + 1111 $\times$ 8 + 111 $\times$ 8 + 11 $\times$ 8 + 1 $\times$ 8

= 888888 + 88888 + 8888 + 888 + 88 + 8

= 987648

And,

123456 $\times$ 8 + 6 = 987648 + 6 = 987648

NCERT solutions for class 6 mathematics chapter wise

Chapters No.	Chapters Name
Chapter - 1	NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers
Chapter - 2	Solutions of NCERT for class 6 maths chapter 2 Whole Numbers
Chapter - 3	CBSE NCERT solutions for class 6 maths chapter 3 Playing with Numbers
Chapter - 4	NCERT solutions for class 6 maths chapter 4 Basic Geometrical Ideas
Chapter - 5	Solutions of NCERT for class 6 maths chapter 5 Understanding Elementary Shapes
Chapter - 6	CBSE NCERT solutions for class 6 maths chapter 6 Integers
Chapter - 7	NCERT solutions for class 6 maths chapter 7 Fractions
Chapter - 8	Solutions of NCERT for class 6 maths chapter 8 Decimals
Chapter - 9	CBSE NCERT solutions for class 6 maths chapter 9 Data Handling
Chapter -10	NCERT solutions for class 6 maths chapter 10 Mensuration
Chapter -11	Solutions of NCERT for class 6 maths chapter 11 Algebra
Chapter -12	CBSE NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
Chapter -13	NCERT solutions for class 6 maths chapter 13 Symmetry
Chapter -14	Solutions of NCERT for class 6 maths chapter 14 Practical Geometry

NCERT solutions for class 6 subject wise

NCERT Solutions for class 6 maths

Solutions of NCERT for class 6 science

How to use NCERT solutions for class 6 maths chapter 2 Whole Numbers?

Please ensure you must have done the previous chapter.
Go through the concepts and observations given in the NCERT textbook.
Take a look through some examples to understand the pattern to answer a specific question.
Implement all the learning while doing the exercise problems.
While doing the exercise problem you can assist yourself by using NCERT solutions for class 6 maths chapter 2 Whole Numbers.

Keep Working hard and happy learning!

Recently Asked Questions

Q.
3. Which can be shown as rectangles?

Q.
1. Write the next three natural numbers after 10999.

Q.
6. Write the predecessor of :
(a) 94 (b) 10000 (c) 208090 (d) 7654321

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NCERT Solutions for Class 6 Maths Chapter 13 Symmetry

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion

NCERT Solutions for Class 6 Maths Chapter 11 Algebra

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NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers

NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Predecessor and Successor

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NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Whole Numbers

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Solutions for NCERT class 6 maths chapter 2 Whole Numbers Exercise: 2.1

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NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Properties of Whole Numbers

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NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.2

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