# NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers

NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers-

Chapter 3 Playing with Numbers starts with solving problems that introduce the concepts of multiples and divisors. As we progress the chapter, multiples, divisors and factors adds fun to the chapter 3 Playing with Numbers in the form of a game. In this chapter, we will learn to obtain the number of multiples and factors of a given number. We will also discuss multiples, divisors, factors and learn how to identify factors and multiples. In this chapter, there are 55 questions in 7 exercises. The  NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers are solved by our subject experts to clear students doubts regarding this topic. These NCERT solutions help them in their preparation of class 6 CBSE final examination. The NCERT solutions for class 6 Maths is the detailed solution of each and every problem of NCERT textbook.

As the NCERT Class 6 Maths Chapter 3 Playing with Numbers progress, students will learn about are prime and composite numbers, tests for divisibility of numbers, common multiples, and common factors, prime factorization, some more divisibility rules, highest common factor (HCF), lowest common multiple (LCM). The Highest Common Factor of two or more given numbers is the highest number of their common factors and the Lowest Common Multiple of two or more given numbers is the lowest number of their common multiples. At the end of the chapter, we will discuss some questions on the HCF and LCM. Let's discuss some important points of NCERT Class 6 Maths Chapter 3 Playing with Numbers-

• A factor of a number is the exact divisor of that number
• Every number is a factor of itself.
• Number 1 is the factor of every number.
• Every factor of a number is less than or equal to that number.
• Every number is a multiple of each of its factors.
• Co-prime numbers are the two numbers with only 1 as a common factor.

Example: Write all the factors of 68.

Solution: We note that

$\\68 = 1 \times 68\\\\ 68 = 2 \times 34\\\\ 68 = 4 \times 17\\\\ 68 = 17 \times 4$

Stop here, because 4 and 17 have occurred earlier. Thus, all the factors of 68 are 1, 2, 4, 17, 34 and 68

## 3.1 Introduction

3.2 Factors and Multiples

3.3 Prime and Composite Numbers

3.4 Tests for Divisibility of Numbers

3.5 Common  Factors  and  Common  Multiples

3.6 Some More Divisibility Rules

3.7 Prime Factorisation

3.8 Highest Common Factor

3.9 Lowest Common Multiple

3.10 Some Problems on HCF and LCM

## NCERT Solutions for Class 6 Mathematics - Chapter-wise

 Chapters No. Chapters Name Chapter - 1 Knowing Our Numbers Chapter - 2 Whole Numbers Chapter - 4 Basic Geometrical Ideas Chapter - 5 Understanding Elementary Shapes Chapter - 6 Integers Chapter - 7 Fractions Chapter - 8 Decimals Chapter - 9 Data Handling Chapter -10 Mensuration Chapter -11 Algebra Chapter -12 Ratio and Proportion Chapter -13 Symmetry Chapter -14 Practical Geometry