NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers- Maths is all about the numbers and in that subject we can simply play with the numbers. NCERT Class 8 Maths Chapter 16 Playing with Numbers is a very interesting chapter. In this, we are not going to really learn any theoretical concept or we are not going to solve any algebraic equation. In this, we are going to learn about some nice mathematical tricks. The important topics in CBSE grade 8 Maths Chapter 16 Playing with Numbers are tests of divisibility like divisibility by 10, 5, 2, 9 and 3, numbers in general form, letters for digits, etc.
In Class 8 Chapter 16 Playing with Numbers, we deal with numbers in general form, games with numbers and also deal with puzzles on arithmetic problems in which letters take place of digit. To strengthen the foundation of the Maths subject and also to develop an interest it must develop the ability to play with the numbers. Sometimes students face problems while solving exercises of NCERT book. So, to help the students and clear their doubts the NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers are prepared and explained by the experts.
Let’s take an example of games with numbers- two friends Meenakshi and Sundaram play a game Minakshi asks Sundaram to think a two-digit number and then-
In NCERT Class 8 Maths Chapter 16 Playing with Numbers, there are 2 exercises with 14 questions. In exercises problems like finding the missing term in the number and problems based on divisibility tests are there.
1. Which of the following is divisible by 3
solution: A number is divisible by three if the sum of the digits if the number is divisible by three. Checking one by one
the sum of digits=3+1+3=7 which is not divisible by 3. So 313 is not divisible by 3
the sum of digits=3+1+6+3=13 which is not divisible by 3. So 3163 is not divisible by 3
the sum of digits=3+1+6+2=12 which is divisible by 3. So 3162 is divisible by 3
the sum of digits=3+1+6+2+6=18 which is divisible by 3. So 31626 is divisible by 3
|Chapter -1||Rational Numbers|
Check what the result would have been if Sundaram had chosen the numbers shown below.
Q1. You have seen that a number 450 is divisible by 10. It is also divisible by 2 and 5 which are factors of 10. Similarly, a number 135 is divisible 9. It is also divisible by 3 which is a factor of 9.
Can you say that if a number is divisible by any number m, then it will also be divisible by each of the factors of m?
Q3. If is a multiple of 3, where is a digit, what is the value of ?
(Since is a multiple of 3, its sum of digits is a multiple of 3; so is one of these numbers: 0, 3, 6, 9, 12, 15, 18, ... . But since is a digit, it can only be that . Therefore, . Thus, can have any of four different values.)