# 5.7 a) A bar magnet of magnetic moment lies aligned with the direction of a uniform magnetic field of 0.22 T.  What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: ii) opposite to the field direction?

Given.

Magnetic moment, M= 1.5

Magnetic field strength, B= 0.22 T

Now,

The initial angle between the axis and the magnetic field, = 0°

Final angle, = 180°

We know, The work required to make the magnetic moment opposite  to the direction of the magnetic field is given as:

= 0.66 J

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