5.7 a) A bar magnet of magnetic moment lies aligned with the direction of a uniform magnetic field of 0.22 T.
What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: ii) opposite to the field direction?
Given.
Magnetic moment, M= 1.5
Magnetic field strength, B= 0.22 T
Now,
The initial angle between the axis and the magnetic field, = 0°
Final angle, = 180°
We know, The work required to make the magnetic moment opposite to the direction of the magnetic field is given as:
= 0.66 J