Q

# Fill in the boxes: (i)

Fill in the boxes:

(i)     $\frac{5}{4}=\frac{\square }{16}=\frac{25}{\square }=\frac{-15}{\square }$                     (ii)     $\frac{-3}{7}=\frac{\square }{14}=\frac{9}{\square }=\frac{-6}{\square }$

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(i) $\frac{5}{4}=\frac{\square }{16}=\frac{25}{\square }=\frac{-15}{\square }$

$\frac{5}{4}$  can be written as:

$\Rightarrow \frac{5}{4} = \frac{5\times4}{4\times4} = \frac{20}{16}$

$\Rightarrow \frac{5}{4} = \frac{5\times5}{4\times5} = \frac{25}{20}$

$\Rightarrow \frac{5}{4} = \frac{5\times-3}{4\times-3} = \frac{-15}{-12}$

Hence, we have

$\frac{5}{4}=\frac{20 }{16}=\frac{25}{20 }=\frac{-15}{-12 }$

(ii) $\frac{-3}{7}=\frac{\square }{14}=\frac{9}{\square }=\frac{-6}{\square }$

$\frac{-3}{7}$  can be written as:

$\Rightarrow \frac{-3}{7} = \frac{-3\times2}{7\times2} = \frac{-6}{14}$

$\Rightarrow \frac{-3}{7} = \frac{-3\times-3}{7\times-3} = \frac{9}{-21}$

$\Rightarrow \frac{-3}{7} = \frac{-3\times2}{7\times2} = \frac{-6}{14}$

Hence, we have

$\frac{-3}{7}=\frac{-6 }{14}=\frac{9}{-21}=\frac{-6}{14 }$

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