# 4. Find the equation of the normal to curve   which passes through the point (1, 2).

Given the equation of the curve

We know that the slope of the tangent at a point on the given curve is given by

We know that

At point (a,b)

Now, the equation of normal with point (a,b) and

It is given that it also passes through the point (1,2)
Therefore,
-(i)
It also satisfies equation                     -(ii)
By comparing equation (i) and (ii)

Now, equation of normal with point (2,1) and  slope = -1

Hence, equation of normal is x + y - 3 = 0

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