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# (i) Is 10 × [(6 + (–2)] = 10 × 6 + 10 × (–2)?

(i)  Is 10 × [(6 + (–2)] = 10 × 6 + 10 × (–2)?

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L.H.S = $10 \times [(6 + (-2)] = 10\times4 =40$

R.H.S =  $10 \times 6 + 10 \times (-2) = 60 + (-20) = 40$

Therefore,L.H.S = R.H.S

Hence, $10 \times [(6 + (-2)] = 10 \times [(6 + (-2)]$

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