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  • The radius of the innermost electron orbit of a hydrogen atom is 5 point 3 multiplied by 10 raise to power minus 11 m What are the radii of the n equal to 2 and n equal to 3 orbits

Q 12.8     The radius of the innermost electron orbit of a hydrogen atom is 5.3 \times 10^{-11}m. What are the radii of the n = 2 and n =3 orbits?

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Given the radius of the innermost electron orbit of a hydrogen atom is r_{o} = 5.3 \times 10^{-11}m.

So, as we know the formula for calculating the radius of the nth orbit.

r =r_{o}.n^2

For n=2 orbit we have,

Radius, r = 5.3\times10^{-11}\times (2)^2

= 2.12\times10^{-10}m

Similarly for n=3,

we have,

Radius, r = 5.3\times10^{-11}\times (3)^2

= 4.77\times10^{-10}m.

Posted by

Divya Prakash Singh

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