# Q. 3.     What is the magnitude of the gravitational force between the earth and a $1\; kg$ object on its surface? (Mass of the earth is $6\times 10^{24}\; kg$  and radius of  the $Q$. earth is$6.4\times 10^{6}\; m.$)

Mass of Earth Mis $6\times 10^{24}\; kg$

Mass of the body m is 1 kg

The radius of the earth RE is $6.4\times 10^{6}\; m.$

Universal gravitational constant, G =$6.67\times 10^{-11}N\ m^{2}\ kg^{-2}$

The magnitude of the gravitational force between the earth and the body would be

$\\F=G\frac{M_{E}m}{r_{E}^{2}}\\ F=6.67\times 10^{-11}\times \frac{6\times 10^{24}\times 1}{(6.4\times 10^{6})^{2}}\\ F=9.77N$

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