Q. 3.     What is the magnitude of the gravitational force between the earth and a 1\; kg object on its surface? (Mass of the earth is 6\times 10^{24}\; kg  and radius of  the Q. earth is6.4\times 10^{6}\; m.)

Answers (1)

Mass of Earth Mis 6\times 10^{24}\; kg

Mass of the body m is 1 kg

The radius of the earth RE is 6.4\times 10^{6}\; m.

Universal gravitational constant, G =6.67\times 10^{-11}N\ m^{2}\ kg^{-2}

The magnitude of the gravitational force between the earth and the body would be

\\F=G\frac{M_{E}m}{r_{E}^{2}}\\ F=6.67\times 10^{-11}\times \frac{6\times 10^{24}\times 1}{(6.4\times 10^{6})^{2}}\\ F=9.77N

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