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Total number of pens = 144 Total number of defective pens = 20  Number of good pens = 144-20 = 124 She will buy if the pen is good. Therefore, the probability that she buys = probability that the pen is good =
Here, Total outcome is the area of the rectangle and favourable outcome is area of the circle. Area of the rectangle =  Area of the circle =
The six faces of the die contains : {A,B,C,D,E,A} Total number of letters = 6 (i) Since there is only one D, number of favourable outcomes = 1 Therefore, the probability of getting D is
The six faces of the die contains : {A,B,C,D,E,A} Total number of letters = 6 (i) Since there are two A's, number of favourable outcomes = 2 Therefore, the probability of getting A is
Total number of discs = 90 Numbers between 1 and 90 that are divisible by 5 are {5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90} Therefore, total number of discs having numbers that are divisible by 5 = 18.
Total number of discs = 90 Perfect square numbers between 1 and 90 are {1, 4, 9, 16, 25, 36, 49, 64, 81} Therefore, total number of discs having perfect squares = 9.
Total number of discs = 90 Number of discs having a two-digit number between 1 and 90 = 81
Total number of bulbs =  20 Hence, total possible outcomes = 20 Number of defective bulbs = 4 Hence, the number of favourable outcomes = 4
Total number of bulbs =  20 Hence, total possible outcomes = 20 Number of defective bulbs = 4 Hence,number of favourable outcomes = 4
Total number of pens = 132(good) + 12(defective) Hence, total possible outcomes = 144 Number of good pens = number of favourable outcomes = 132
When the queen is kept aside, there are only 4 cards left Hence, the total possible outcomes = 4 (2b) Since there is no queen left. Hence, favourable outcome = 0 Therefore, the probability of getting a queen is 0. Thus, it is an impossible event.
When the queen is kept aside, there are only 4 cards left Hence, the total possible outcomes = 4 (2a) There is only one ace. Hence, favourable outcome = 1 Therefore, the probability of getting an ace is 0.25
Total number of cards = 5 Hence, the total possible outcomes = 5 (1) There is only one queen. Hence, favourable outcome = 1
Total number of cards in a well-shuffled deck = 52 Hence, total possible outcomes = 52 (6) Let E be the event of getting the queen of diamonds Hence, the number of favourable outcomes = 1 Therefore, the probability of getting the queen of diamonds is
Total number of cards in a well-shuffled deck = 52 Hence, total possible outcomes = 52 (5) Let E be the event of getting a spade. There are 13 cards in each suit. {2,3,4,5,6,7,8,9,10,J,Q,K,A} Hence, number of favourable outcomes = 13 Therefore, the probability of getting a spade is
Total number of cards in a well-shuffled deck = 52 Hence, total possible outcomes = 52 (4) Let E be the event of getting the jack of hearts Hence, the number of favourable outcomes = 1 Therefore, the probability of getting the jack of hearts is
Total number of cards in a well-shuffled deck = 52 Hence, total possible outcomes = 52 (3) Let E be the event of getting a red face card. Face cards: (J, Q, K) of hearts and diamonds Hence, number of favourable outcomes = 3x2 = 6 Therefore, the probability of getting a red face card is
Total number of cards in a well-shuffled deck = 52 Hence, total possible outcomes = 52 (2) Let E be the event of getting a face card. Face cards: (J, Q, K) of each four suits Hence, number of favourable outcomes = 12 Therefore, the probability of getting a face card is
Total number of cards in a well-shuffled deck = 52 Hence, total possible outcomes = 52 (1) Let E be the event of getting a king of red colour. There are only red colour kings: Hearts and diamonds Hence, number of favourable outcomes = 2 Therefore, the probability of getting a king of red colour is
Possible outcomes when a die is thrown = {1,2,3,4,5,6} Number of possible outcomes once = 6 (iii) Let O be the event of getting an odd number. Odd numbers on the die are = {1,3,5} Number of favourable outcomes = 3 Therefore, the probability of getting an odd number is
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